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erma4kov [3.2K]
2 years ago
10

What is the value of X? Pls help!

Mathematics
1 answer:
Licemer1 [7]2 years ago
6 0

Answer:

42

Step-by-step explanation:

Since the scale factor is 2:7, you can divide the given number by 2 then multiply it by 7, so 12/2x7=42

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263/4 options 65r2 64r7 65 65r3
Reika [66]

Answer:

65R3

Step-by-step explanation:

260/4 is a whole number, so then there would be a remainder 3. The only one with a r3 is D.

Hope this helps :D

4 0
2 years ago
4. Solve the following equation: 9x - 6 +7x = 16x - 6
Mashutka [201]

Answer: the answer is 0=0

Step-by-step explanation:

7 0
2 years ago
city planner is making a scale model of his city for his office building. The model has a coordinate grid where each unit is 1 m
Lelechka [254]

Answer:

(4, 1)

Step-by-step explanation:

For any rectangle or square located on the axes, match the pairs and find what's missing. 3 -- 3, 4 -- 4. unmatched are 4 and 1. 4 is x because it's missing from x and same for 1 and y.

plz mark me Brainliest

This has already been asnwered on brainly

5 0
3 years ago
Find the zeros of the polynomial function and state the multiplicity of each.
zheka24 [161]
\bf f(x) = 4(x + 7)^2(x - 7)^3\implies 0 = 4(x + 7)^2(x - 7)^3
\\\\\\
0=(x+7)^2(x-7)^3\implies 
\begin{cases}
0=(x+7)^7\\
\qquad 0=(x+7)(x+7)\\
\qquad -7=x\\
\qquad -7=x\\
----------\\
0=(x-7)^3\\
\qquad 0=(x-7)(x-7)(x-7)\\
\qquad 7=x\\
\qquad 7=x\\
\qquad 7=x
\end{cases}

the -7 is found there twice, so it has a multiplicity of 2
the +7 is there thrice, so it has multiplicity of 3
7 0
2 years ago
Given that sin theta = 1/4, 0
GaryK [48]
Answer: cos(Θ) = (√15) / 4

Explanation:

The question states:

1) sin(Θ) = 1/4

2) 0 < Θ < π / 2

3) find cos(Θ)

This is how you solve it.

1) Use the fundamental identity (in this part I use α instead of Θ, just for facility of wirting the symbols, but they mean the same for the case).

(cos \alpha )^2 + (sin \alpha )^2 =1

2) From which you can find:

(cos \alpha )^2 = 1 - (sin \alpha )^2

3) Replace sin(α) with 1/4

=> (cos \alpha )^2 = 1 - (1/4)^2 = 1 - 1/16 = 15/16

=> cos \alpha =+/- \sqrt{15/16} = +/- (\sqrt{15} )/4

4) Given that the angle is in the first quadrant, you know that cosine is positive and the final answer is:

cos(Θ) = \sqrt{15} /4.

And that is the answer.
6 0
3 years ago
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