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andrezito [222]

2 years ago

14

PLEASE HELP ME!!!!

2 answers:

tigry1 [53]2 years ago

6 0

1/8x2 and 4x I had usa test prep

swat322 years ago

3 0

Answer:

The focus would lie at (-8,16)

Step-by-step explanation:

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PLEASEEEE HELP!! Which answer is correct??

loris [4]

y = 4x+4

y = -3x-3

so 4x+4=-3x-3

7x=-7

x=-1

so (-1,0)

8 0

2 years ago

Rearrange the formula I = √P/R for R.

katrin2010 [14]

Answer:

A) R = P/I²

Step-by-step explanation:

I = √P/R

Square each side

I^2 = (√P/R)^2

I^2 = P/R

Multiply each side by R

I^2R =P/R * R

I^2R = P

Divide by I^2

I^2R / I^2 = P/ I^2

R = P/ I^2

3 0

2 years ago

A total of 17,100 seats are still available for the next hockey game. If 62% of the tickets are sold, how many seats are in the

MrRa [10]

Answer:

We have

seats x ( 62 / 100 ) = (seats - 17,100);

seats x 62 = 100 x (seats - 17,100);

seats x 62 = seats x 100 - 1710000;

1,710,000 = seats x 38;

seats = 1,710,000 ÷ 38;

seats = 45,000;

The correct answer is c. 45,000 seats;

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

4 0

3 years ago

Read 2 more answers

A right rectangular prism is 5 3/4 cm wide, 10 1/2 cm long, and 8 cm tall.

irina1246 [14]

Answer:

Multiply all the numbers and you will get your answer. It is 483 cm^3

Hope this helped, have an awesome day and please mark brainliest if u want too.

4 0

2 years ago