Brenda throws a dart at this square-shaped target: Part A: Is the probability of hitting the black circle inside the target clos er to 0 or 1? Explain your answer. (5 points) Part B: Is the probability of hitting the white portion of the target closer to 0 or 1? Explain your answer. (5 points)
1 answer:
Either way. The probability of hitting the circle is: P(C)=Area of circle divided by area of square P(W)=(area of square minus area of circle divided by area of square P(C)=(πr^2)/s^2 P(W)=(s^2-πr^2)/s^2 ... Okay with know dimensions, r=1 (because r=d/2 and d=2 so r=1), s=11 we have: P(inside circle)=π/121 (≈0.0259 or 2.6%) P(outside circel)=(121-π)/121 (≈0.9744 or 97.4%)
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Step-by-step explanation:
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one solution
Step-by-step explanation:
3(x-2) =22 -x
Distribute
3x - 6 = 22-x
Add x to each side
3x+x-6 = 22-x+x
4x+6 = 22
Subtract 6 from each side
4x+6-6 = 22-6
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