(-3, -3) and (2, 7).
The solutions to a graphed system of equations are where the two graphs cross each other. So in this case the two equations cross at (-3, -3) and (2, 7), and those points are the solutions to the system of equations.
136 - 3x = 40 +5x
136 - 40 = 5x + 3x
96 = 8x
12 = x
40 + 4(12)
40 + 48
88
A.) 12 weeks
B.) $88
Answer:
f(-3) = -2
f(-2.6) = -2
f(0.6) = 2.4
f(4.5) = 8.5
Step-by-step explanation:
(Whole question:
Evaluate the piecewise function for the given values.
Find f(-3), f(-2,6), f(0.6), and f(4.5) for f(x)={ -2 If x ≤ 0 4x. If 0 <x <1. x + 4. If x ≥ 1)
As the piecewise function shows, the function f(x) has the value of -2 for values of x lesser or equal than 0, has the value of 4x if the value of x is between 0 and 1, and has the value of x+4 for values of x greater or equal than 1.
So, for f(-3), the value of x is lesser than 0, so we have that f(-3) = -2
For f(-2.6), the value of x is lesser than 0, so we have that f(-3) = -2
For f(0.6), the value of x is between 0 and 1, so we have that f(0.6) = 4*0.6 = 2.4
For f(4.5), the value of x is greater than 1, so we have that f(4.5) = 4.5 + 4 = 8.5
Answer:
0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
Find the probability that he weighs between 170 and 220 pounds.
This is the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 170.
X = 220
has a pvalue of 0.6554
X = 170
has a pvalue of 0.2743
0.6554 - 0.2743 = 0.3811
0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.
Hello from MrBillDoesMath!
Answer:
t = i /(Pr)
Discussion:
i = Prt => (divide both sides by "Pr")
i/(Pr) = (Prt)/(Pr)
= (Pr)t/(Pr)
= t (as (Pr)/(Pr) = 1)
Thank you,
MrB
