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aliya0001 [1]
3 years ago
13

Cost of an oil change: $19.95 Discount: 33% What is the new cost?

Mathematics
2 answers:
marysya [2.9K]3 years ago
5 0

Answer:

$13.95

Step-by-step explanation:

valina [46]3 years ago
3 0

Answer:

The new cost is 13.37

Step-by-step explanation:

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What is the slope of the line?<br><br> A. 2<br> B. -2<br> C. 1/2<br> D. -1/2
iogann1982 [59]

slope m = - 2 → B

calculate m using the ' gradient formula '

m = (y₂ - y₁)/(x₂ - x₁)

choosing 2 'clear ' coordinates from the graph of the line

(x₁, y₁) = (0, 7) and (x₂, y₂) = (7, - 5\frac{(- 5 - 7)}{(6 - 0)}) = \frac{- 12}{6} = - 2


m =

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3 years ago
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In the inequality, what are all the possible values of x?
Marat540 [252]

Answer:

B) \displaystyle x ≤ 0

Step-by-step explanation:

2(x + 12) − 16 ≤ 8

\displaystyle \frac{2(x + 12)}{2} ≤ \frac{24}{2} \\ \\ x + 12 ≤ 12 \\ \\ x ≤ 0

I am joyous to assist you anytime.

7 0
3 years ago
Can some one help please help me
Vedmedyk [2.9K]

Answer:

5\:\:and\:\:7 are the required consecutive odd integers.

Step-by-step explanation:

Let's say, the two consecutive odd integers be, x and x+2.

x\left(x+2\right)=2\left(x+2\right)+21\\\\x^2+2x=2x+4+21\\\\\mathrm{Subtract\:}2x\mathrm{\:from\:both\:sides}\\\\x^2+2x=2x+25\\\\x^2+2x-2x=2x+25-2x\\\\x^2=25\\\\x=5

5 0
3 years ago
What is the probability of obtaining 5 heads from 5 coin flips? Give your answer to 5 decimal places.
katovenus [111]

Answer:

0.03125 = 3.125% probability of obtaining 5 heads from 5 coin flips.

Step-by-step explanation:

For each coin flip, there are only two possible outcomes. Either it is heads, or it is tails. The probabilities for each flip are independent from each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

For each coin toss, heads and tails are equally as likely, so p = \frac{1}{2} = 0.5}

What is the probability of obtaining 5 heads from 5 coin flips?

This is P(X = 5) when n = 5.

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.5)^{5}.(0.5)^{0} = 0.03125

0.03125 = 3.125% probability of obtaining 5 heads from 5 coin flips.

6 0
3 years ago
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