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mestny [16]
3 years ago
5

How do I put this rational expression in simplest form? Steps please!!!!

Mathematics
2 answers:
Cloud [144]3 years ago
8 0
4.
b^-2-x^-2/b^-1+x^-1

b^-2/b^-1=b^-1
x^-2/x^-1=x^-1
As a result, the simplest form is:
b^-1-x^-1. Hope it help!
Leno4ka [110]3 years ago
6 0
\bf a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad

\cfrac{1}{a^{ n}}\implies a^{-{ n}}\\\\
-----------------------------\\\\
\cfrac{b^{-2}-x^{-2}}{b^{-1}-x^{-1}}\implies \cfrac{\frac{1}{b^2}-\frac{1}{x^2}}{\frac{1}{b}+\frac{1}{x}}\implies \cfrac{\frac{x^2-b^2}{b^2x^2}}{\frac{x+b}{bx}}\implies \cfrac{x^2-b^2}{b^2x^2}\cdot \cfrac{bx}{x+b}\\\\


\bf -----------------------------\\\\
\textit{now recall your }\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
\cfrac{(x-b)\underline{(x+b)}}{\underline{(bx)^2}}\cdot \cfrac{\underline{bx}}{\underline{x+b}}\implies \cfrac{x-b}{bx}
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