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grigory [225]
3 years ago
13

An owner of a key rings manufacturing company found that the profit earned (in thousands of dollars) per day by selling n number

of key rings is given by , where n is the number of key rings in thousands. Find the number of key rings sold on a particular day when the total profit is $5,000.
Mathematics
1 answer:
vovikov84 [41]3 years ago
7 0

Answer:

The number of key rings sold on a particular day when the total profit is $5,000 is 4,000 rings.

Step-by-step explanation:

The question is incomplete.

<em>An owner of a key rings manufacturing company found that the profit earned (in thousands of dollars) per day by selling n number of key rings is given by </em>

<em />P=n^2-2n-3<em />

<em>where n is the number of key rings in thousands.</em>

<em>Find the number of key rings sold on a particular day when the total profit is $5,000.</em>

<em />

We have the profit defined by a quadratic function.

We have to calculate n, for which the profit is $5,000.

P=n^2-2n-3=5\\\\n^2-2n-8=0

We have to calculate the roots of the polynomial we use the quadratic equation:

n=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\n= \frac{-2\pm\sqrt{4-4*1*(-8)}}{2}= \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{36}}{2} =\frac{-2\pm6}{2} \\\\n_1=(-2-6)/2=-8/2=-4\\\\n_2=(-2+6)/2=4/2=2

n1 is not valid, as the amount of rings sold can not be negative.

Then, the solution is n=4 or 4,000 rings sold.

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