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2 years ago

What is the rule for reflecting in the x=c line

Mathematics

1 answer:

Slav-nsk [51]2 years ago

7 0

Answer:

What is the rule for a reflection across the line y =- X?

When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. If you reflect over the line y = -x, the x-coordinate and y-coordinate change places and are negated (the signs are changed). the line y = x is the point (y, x).

Step-by-step explanation:

There is no rule about x=C..

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You have a credit card with a balance of $754.43 at a 13.6% APR. You have $300.00 available each month to save or pay down your

pochemuha

<span>B(n) = A(1 + i)^n - (P/i)[(1 + i)^n - 1]

where B is the balance after n payments are made, i is the monthly interest rate, P is the monthly payment and A is the initial amount of loan.

We require B(n) = 0...i.e. balance of 0 after n months.

so, 0 = A(1 + i)^n - (P/i)[(1 + i)^n - 1]

Then, with some algebraic juggling we get:

n = -[log(1 - (Ai/P)]/log(1 + i)

Now, payment is at the beginning of the month, so A = $754.43 - $150 => $604.43

Also, i = (13.6/100)/12 => 0.136/12 per month

i.e. n = -[log(1 - (604.43)(0.136/12)/150)]/log(1 + 0.136/12)

so, n = 4.15 months...i.e. 4 payments + remainder

b) Now we have A = $754.43 - $300 = $454.43 so,

n = -[log(1 - (454.43)(0.136/12)/300)]/log(1 + 0.136/12)

so, n = 1.54 months...i.e. 1 payment + remainder
</span>

8 0

3 years ago

Mell is twice as old as Jerry. If 16 is subtracted from Mell’s age and 16 is added to Jerry’s age, their ages will be equal. Wha

irga5000 [103]

Answer:

Step-by-step explanation:

Let J = Jerry's age

Let M = Mary's age = 2J

M - 16 = J + 16

Substitute 2J for Mary's age

2J - 16 = J + 16

2J - J - 16 = 16

J = 16 + 16

J = 32

Jerry is 32.

Mary is twice as old as Jerry.

Mary is 2(32) = 64

3 0

3 years ago

Read 2 more answers

Polygon D is a scaled copy of polygon C using a scale factors of 6

Vladimir79 [104]

Answer: The area of the Polygon D is 36 times larger than the area of the Polygon C.

Step-by-step explanation:

<h3> The complete exercise is: "Polygon D is a scaled copy of Polygon C using a scale factor of 6. How many times larger is the area of Polygon D than the area Polygon C"?</h3>

In order to solve this problem it is important to analize the information provided in the exercise.

You know that the Polygon D was obtained by multiplying the lengths of the Polygon C by the scale factor of 6.

Then, you can identify that the Length scale factor used is:

$Length\ scale\ factor=k=6$

Now you have to find the Area scale factor.

Knowing that the Length scale factos is 6, you can say that the Area scale factor is:

$Area \ scale\ factor=k^2=6^2$

Finally, evaluating, you get that this is:

$Area \ scale\ factor=36$

Therefore, knowing the Area scale factor, you can determine that the area of the Polygon D is 36 times larger than the area of the Polygon C.

8 0

3 years ago

2 numbers are such that if 7 is added to the first number, a number twice the second number is obtained. If 20 is added to the s

Eduardwww [97]

Answer:

1st= 47/7 or 6.71

2nd= 48/7 or 6.857

Step-by-step explanation:

1st number =X and 2nd number = Y

According to question, X+7=2Y

20+Y=4X

X=2Y-7 (from 1st condition)

putting in it second

20+Y=4(2Y-7)

20+Y=8Y-28

20+28=8Y-Y

48=7Y

Y=48/7

so X=2(48/7)-7

=96-49/7

47/7

5 0

2 years ago

The plate is rotated 90° about the origin in the counterclockwise direction. In the image trapezoid, what are the coordinates of

Jet001 [13]

Answer:

The coordinates of the endpoints of the side congruent to side EF is:

E'(-8,-4) and F'(-5,-7).

Step-by-step explanation:

<em>" when point M (h, k) is rotated about the origin O through 90° in anticlockwise direction or we can say counter clockwise. The new position of point </em><em>M (h, k) will become M' (-k, h) "</em>

We are given a trapezoid such that the vertices of trapezoid are:

E(-4,8) , F(-7,5) , G(-4,3) , H(-2,5)

Then the new coordinates after the given transformation is:

E(-4,8) → E'(-8,-4)

F(-7,5) → F'(-5,-7)

G(-4,3) → G'(-3,-4)

H(-2,5) → H'(-5,-2)

Hence the coordinates of the endpoints of the side congruent to side EF is:

E'(-8,-4) and F'(-5,-7).

4 0

3 years ago