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3 years ago

What is the volition of -3 (2x + 5)=-3? 5

Mathematics

2 answers:

kumpel [21]3 years ago

7 0

The answer to this question is -2

Artyom0805 [142]3 years ago

4 0

Answer:

x = - 2

Step-by-step explanation:

Given

- 3(2x + 5) = - 3 ( divide both sides by - 3 )

2x + 5 = 1 ( subtract 5 from both sides )

2x = - 4 ( divide both sides by 2 )

x = - 2

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Lily has 642 stamps in total. She has 54 US stamps than foreign stamps. How many does she have each

maw [93]

Answer:

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Step-by-step explanation:

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2 years ago

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What is the following quotient? 2- 8sqr / 4+12 sqr

AlekseyPX

Answer: 130

Step-by-step explanation:

--> first solve sqr-->2-64/4+144

-->perform division next as per DMAS rule-->64÷4=16--> 2-16+144

--> now perform addition and subtraction-->2-16-14--> -14+144= 130

7 0

3 years ago

Necesito las respuestas

Stels [109]

Answer:

I need it in English please so I can helps

3 0

1 year ago

Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:

tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

$Q1 = \frac{N +1}{4}th$

So, we have:

$Q1 = \frac{13 +1}{4}th$

$Q1 = \frac{14}{4}th$

$Q1 = 3.5th$

This is the average of the 3rd and the 4th element

$Q1 = \frac{1}{2} \times (84 + 91)$

$Q1 = 87.5$

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

$Q3 = 3 \times \frac{N +1}{4}th$

So, we have:

$Q3 = 3 \times \frac{13 +1}{4}th$

$Q3 = 3 \times 3.5th$

$Q3 = 10.5th$

This is the average of the 10th and the 11th element.

$Q_3 =\frac12 \times (98 + 101)$

$Q_3 =99.5$

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

$IQR = Q_3 -Q_1$

$IQR = 99.5 - 87.5$

$IQR = 12$

Also, we have:

$IQR(1.5) = 12 \times 1.5$

$IQR(1.5) = 18$

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

$Lower = Q_1 - IQR(1.5)$

$Lower = 87.5- 18$

$Lower = 69.5$

$Upper = Q_3 + IQR(1.5)$

$Upper = 99.5 + 18$

$Upper = 117.5$

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120