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gayaneshka [121]
3 years ago
12

If f (x) = x and g(x) = 3x + 1 are two real functions. Find (f + g) (x)

Mathematics
1 answer:
romanna [79]3 years ago
4 0

Answer:

4x + 1

Step-by-step explanation:

note that (f + g)(x) = f(x) + g(x) , thus

f(x) + g(x)

= x + 3x + 1 ← collect like terms

= 4x + 1

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Which represents the solution set of 5(x+5) < 85?
Maru [420]

Answer:

\Huge \boxed{X

Step-by-step explanation:

To solve this problem, first you have to isolate it on one side of the equation. Remember to solve this problem, find represents the solution of 5(x+5)<85.

First, you divide by 5 from both sides.

\displaystyle \frac{5(x+5)}{5}

Solve.

\displaystyle 85\div5=17

\displaystyle x+5

Next, subtract 5 from both sides.

\displaystyle x+5-5

Solve.

\displaystyle 17-5=12

As a result, the correct answer is x<12.

<h2>Hope this helps! </h2><h2 /><h2>Have a wonderful blessing day! :)</h2><h2 /><h2>Good luck! :)</h2>
3 0
3 years ago
3.11 A shipment of 7 television sets contains 2 defective sets. A hotel makes a random purchase of 3 of the sets. If x is the nu
djverab [1.8K]

Answer:

Probability distribution for x:

P(x=0)=0.3644\\\\P(x=1)=0.4373\\\\P(x=2)=0.1749\\\\P(x=3)=0.0233\\\\

Step-by-step explanation:

We can model the number of defective sets in the group of TV sets (variable x) as a binomial variable, with sample size=3 and probability of success p=2/7≈0.2857.

The probability of k defective sets in the group is:

P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}

So, we have this probabilty distribution for x:

P(x=0) = \dbinom{3}{0} p^{0}q^{3}=1*1*0.3644=0.3644\\\\\\P(x=1) = \dbinom{3}{1} p^{1}q^{2}=3*0.2857*0.5102=0.4373\\\\\\P(x=2) = \dbinom{3}{2} p^{2}q^{1}=3*0.0816*0.7143=0.1749\\\\\\P(x=3) = \dbinom{3}{3} p^{3}q^{0}=1*0.0233*1=0.0233\\\\\\

7 0
3 years ago
What is the word form of
jonny [76]
B/12=
b divided by 12
8 0
2 years ago
Quadrilateral ABCD with vertices A(4, 3), B(4, -2), C(-4, -2) and D(-4, 3) is a rectangle, find the length of the diagonals.
marin [14]
Distance between two points P(x1,y1), Q(x2,y2):
D=sqrt((x2-x1)^2+(y2-y1)^2)

Polygons are generally named in order along the perimeter, so that for a rectangle ABCD, AC or BD are diagonals.
Here, we need the distance between points A(4,3) and C(-4,-2)
Applying the above formula for distance between two points, 

D=sqrt((4-(-4))^2+(3-(-2))^2)=sqrt(8^2+5^2)=sqrt(64+25)=sqrt(89)
6 0
3 years ago
Evaluate the expression when a=1\4 and b=6. -8ab
tester [92]

Answer:

-12

Step-by-step explanation:

-8 * ( 1/4) * (6)

= -12

4 0
3 years ago
Read 2 more answers
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