Answer:
y=-14acfr+5x
Step-by-step explanation:
hope it helps
To find the root, replace y with 0
X^2-12x+35=0
A=1 B=-12 C=35
B^2-4ac=(-12)^2 -4(1)(35)
=144 -140
=4
x=(-b+/- square root of b^2 -4ac) /over/ (2a)
Plug in the numbers
x=-(-12) sqr (-12)^2 4(1)(35) / (2)(1)
X=12 +/-sqr 4 / 2
Positive outcome
x=12 + sqr 4 / 2
x=12+2/2
x=7 <— this one
Negative outcome
x=12-2i/2
x=6-i
Vertex: (6,-1)
In order to solve this we need to get x by itself on one side.
We need o start by adding across the 4 so that we get:
x/3 = -7 + 4 = -3
We then need to multiply both sides by 3 to get a singular x:
x = -3 * 3 = -9
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