Because they are prokaryotic cells.
Answer: C
Explanation: The process that occurred in the lake is natural selection. In the presence of an external environmental influence such as pollution, only the trouts that were fit to survive or in other words those that have the alleles that help in adapting to the new conditions live and increased in numbers. In such a case, one can say the fittest of the organisms survived and the corresponding allelic frequency in that population increased over time. The organisms carrying the other alleles died due to pollution and hence the overall frequency of alleles change.
Answer:
Image result for what is the purpose of greenhouse gases
Greenhouse gases are certain molecules in the air that have the ability to trap heat in the Earth's atmosphere. Some greenhouse gases, like carbon dioxide (CO2) and methane (CH4), occur naturally and play an important role in Earth's climate. If they didn't exist, the planet would be a much colder place.
Explanation:
Answer:
Map distance = Genetic distance, GD = 3.9 MU ≅ 4 MU
Explanation:
The more separated two genes are, the more chances of recombination there will be. The closer they are, the fewer chances of recombination there will be. Two genes that are very close will have a few recombination events and are strongly bounded.
To analyze the recombination frequency, we have to know that:
- 1% of recombination = 1 map unit = 1centi Morgan = 1,000,000 base pairs.
- And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products one of them results in a recombinant one.
Knowing that the genes are linked, we can calculate genetic distances between them. First, we need to identify the genotypes of the parental gametes with the ones of the recombinants. We can recognize the parental gametes in the descendants because their phenotypes are the most frequent, while the recombinants are the less frequent. So:
Parentals:
- black, curved 337
- yellow, straight 364
Recombinants:
- Black, straight 17
- yellow, curved 12
To calculate the recombination frequency we will make use of the next formula: P = Recombinant number / Total of individuals.
P = Recombinant number / Total of individuals.
P = 17 + 12 / 337 + 364 + 17 + 12
P = 29 / 730
P = 0.039
The genetic distance (GD) will result from multiplying that recombination frequency (P) by 100 and expressing it in map units (MU).
GD = P x 100
GD = 0.039 x 100
GD = 3.9 MU ≅ 4 MU
Answer: 2.5-3.o grams per body weight
Explanation:
