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2 years ago

Carbonized fossils are made of:

1 answer:

8 0

Carbonized remains are thin, approximately two-dimensional films of carbon preserved on a flat surface of rock. They are most often black in color, reflecting the fact that they composed mostly of carbon (as is coal, which is also black in color). Most fossils that exhibit “soft part” preservation are carbonizations.

I would say the answer is the Carbon remains of the original organism.

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Which population dispersion pattern is most commonly seen in the field for most species?

laiz [17]

<h2>Types of Dispersion Patterns </h2>

If you're hiking through a forest, you might notice that some species of plants - like certain flowers or bushes - seem evenly spaced, while others - like wild mushrooms - are clustered together in only certain parts of the habitat.

Within any given plant or animal population, or group of individuals of the same species living in the same area, individuals can be spaced in different ways called dispersion patterns. There are three types of dispersion patterns.
Clumped dispersion is when individuals in a population are clustered together, creating some patches with many individuals and some patches with no individuals. In uniform dispersion, individuals are spaced evenly throughout an area. And in random dispersion, individuals are arranged without any apparent pattern.
In natural populations, random dispersion is rare, while clumped dispersion, which we'll focus on in this lesson, is the most common pattern.
Clumped dispersion is often due to an uneven distribution of nutrients or other resources in the environment. It can also be caused by social interactions between individuals. Additionally, in organisms that don't move, such as plants, offspring might be very close to their parents and show clumped dispersion patterns. Let's further examine each of these three reasons for clumped dispersion.

Hope it helps! :)

JoshGonzalez, and NolanGonzalez!

I love u :) 

7 0

2 years ago

Hematopoiesis refers to the formation of blood cells within the red marrow cavities of certain bones. hematopoiesis refers to th

jek_recluse [69]

A. true.

All of our blood cells are derived from haematopoietic stem cells. This cells originate other blood cells through the process of haematopoiesis and are located on the red bone marrow of long bones (inside the diaphysis of the bone).

3 0

2 years ago

How does the pitcher plant digest insects?

mihalych1998 [28]

Q#1
- Carnivorous plants decoy insects by sweet scent or color.
- Not expecting threats insects sit on the plant. This catches them using mechanical traps or sticky substances.
- Then, the plant produces digestive enzymes that break down proteins, fats and sugars which make up the body of the victims for simple compounds which plant can absorb.
Q#2. Carnivorous plants grow in mineral-poor soil, raise substances necessary for life from the bodies of trapped animals. They hunt animals, so that the surface on which they grow, no nutrients they need.
Q#3.Plants by digesting insects provide each large dose of nitrates are lacking in the soil.
Q#4.When a pitcher plant is grown in nitrogen rich soil it grows tall. Insects are it's food source so if it doesn't get any food, it will starve. 
hope i helped

6 0

2 years ago

An adolescent is admitted to the icu in diabetic ketoacidosis. the physician orders a continuous insulin infusion of 100u nph in

stiks02 [169]

I do not know how to work the problem out at the given time. However, If you are answering a multiple choice answer test, this is the answer.

0.2 U/mL

6 0

2 years ago

A solution of acetic acid is prepared in water by adding 11.1 g of sodium acetate to a volumetric flask and brining in the volum

velikii [3]

Answer:

The concentration of

the Acetic Acid is 0.0325M

the Sodium Acetate is 0.1028M

Explanation:

Given

The dissociation of acetic acid is

CH3COOH + CH3COO- + H+ + HA -> A- + H+

We calculate the molarity of sodium acetate by using

Molarity = Moles/Volume

The formula weight of sodium acetate is 82.03 g/mol.

Moles = 11.1g/82.03g/mol

= 0.1353M

Since the volume is 1L, the molarity of sodium acetate will still be 0.1353M

The starting concentration of sodium acetate is 0.1353M

The final concentration of sodium acetate is the starting amount of sodium acetate, minus the amount that was protonated.

Assume that, x = concentration of acetic acid, which is the amount of sodium acetate that was protonated.

From the Henderson-Hasselbalch equation

PH = pKa + log[A-]/[HA]

[A-] = 0.1353 - x

[HA] = x

pKa = 4.75

PH = 5.25

Substitute in these values

5.25 = 4.75 + log(0.1353-x)/x

log(0.1353 - x)/x = 5.25 - 4.75

log(0.1353-x)/x = 0.5

log(0.1353 - x)/x = ½

(0.1353-x)/x = 10^½

(0.1353 - x)/x = 3.1623

0.1353 - x = 3.1623x

0.1353 = x + 3.1623x

0.1353 = 4.1623x

x = 0.1353/4.1623

x = 0.0325M

Therefore [HA] = x = 0.0325M

[A-] = 0.1353 - x = 0.1353 - 0.0325 =

[A-] = 0.1028M

8 0

2 years ago