The balanced equation for the reaction is as follows
2H₂ + O₂ --> 2H₂O
stoichiometry of H₂ to O₂ is 2:1
number of H₂ moles - 30.0 g / 2 g/mol = 15 mol
number of O₂ moles - 80.0 g / 32 g/mol = 2.5 mol
limiting reactant is the reagent in which only a fraction is used up in the reaction
if H₂ is the limiting reactant
if 2 mol of H₂ requires 1 mol of O₂
then 15 mol of H₂ requires 1/2 x 15.0 = 7.5 mol of O₂
but only 2.5 mol of O₂ is required
this means that O₂ is the limiting reagentt and H₂ is in excess
Sodium is a silver-colored metal which is soft enough to cut with a knife. It is an extremely reactive metal, and is always found naturally in ionic compounds, not in its pure metallic form. Pure sodium metal reacts violently (and sometimes explosively) with water, producing sodium hydroxide, hydrogen gas, and heat:
Chlorine is a poisonous, yellow-green gas, with a very sharp odor, a
Chemical change happen cuz these 2 elements will combine to form a new compound which’s NaCl ( table salt )
Explanation:
Gold conducts heat and electricity. ...
Gold is ductile: It can be drawn out into the thinnest wire. ...
Gold is highly reflective of heat and light. ...
Gold is prized for its beauty. ...
Gold is malleable, so it can be flattened into extremely thin sheets.
on the other hand Gold consist of copper
Key Properties of Copper Alloys
Excellent heat conductivity.
Excellent electrical conductivity.
Good corrosion resistance.
Good biofouling resistance.
Good machinability.
Retention of mechanical and electrical properties at cryogenic temperatures.
Non-magnetic.
so the difference is that copper is less expensive and not priced with its beauty
The answer is 4.69 x 10⁻¹⁹ I hope this helped!
Answer:
Explanation:
Hello there!
In this case, since these mole-mass relationships are understood in terms of the moles of the atoms forming the considered compound, we first realize that the chemical formula of the cobalt (III) nitrate is Co(NO₃)₃ whereas there is a 1:1 mole ratio of the cobalt (III) ion (molar mass = 58.93 g/mol) to the entire compound. In such a way, we first compute the moles of the salt (molar mass = 58.93 g/mol) and then apply the aforementioned mole ratio to obtain the grams of the required cation:
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