The percent yield of CO₂ is 93.3%.
<h3>What is the percent yield of CO₂?</h3>
The percent yield of a substance is given as follows:
- Percent yield = actual yield/theoretical yield * 100 %
The equation of the reaction is used to determine the theoretical yield.
- NaHCO₃ + CH₃COOH → CH₃COONa + H₂O + CO₂
Moe ratio of sodium bicarbonate and CO₂ is 1 : 1.
Given that sodium bicarbonate is the limiting reactant, the theoretical yield of CO₂ will be:
Moles of NaHCO₃ reacting = 2.01/84 = 0.0239 moles
Theoretical yield of CO₂ = 0.0239 moles * 22.4L/mol = 0.536 L
Actual yield = 0.50 L
Percent yield = 0.50/0.536 * 100%
Percent yield = 93.3%
In conclusion, the percent yield is the ratio of the actual yield and theoretical yield.
<em>Note that the complete question is given below:</em>
<em>Calculate your % yield of co2 in the reaction based on the grams of nahco3 being the limiting reagent in the reaction between 2.01 g of sodium bicarbonate and 24.6 mL of 1.5 M acetic acid? They produce 0.50 L of at s.t.p.</em>
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Answer:
Explanation:
Hello!
In this case, since the heat involved during a heating process is computed in terms of mass, specific heat and temperature change as shown below:
Thus, since the heated mass of water was 88 g, the specific heat of water is 4.184 J/g°C and the temperature change is 6.0 °C, we can compute the heat as shown below:
Best regards!
<h3>
Answer:</h3>
Sodium
<h3>
Explanation:</h3>
- To answer the question we need to know a few things.
What are cations?
- Cations are positively charged ions that are formed when an atom of an element loses an electron(s).
What elements form cations?
- Metallic elements form cations since they react by losing electrons thus forming ions with a positive charge.
- For example, alkali metals such as sodium form cations with a charge of +1.
- In this case, sodium will form a cation with a charge of + 1, Na⁺
What are negatively charged ions?
- Negatively charged ions are known as anions.
- They are formed by non-metallic elements such as sulfur, argon, silicon, etc.
Hey there!
Given the reaction:
P4 + 10 Cl2 ------------------ 4 PCl5
Molar mass P4 = 124 g/mol
Number of moles P4:
n = mass of solute / molar mass
n = 24.0 / 124
n = 0.1935 moles of P4
Therefore:
1 mole P4 --------------- 4 moles PCl5
0.1935 moles P4 ------- moles PCl5
moles PCl5 = 0.1935 * 4
= 0.774 moles of PCl5
Hope that helps!
Answer:
1. Solubility will increase, because as T increases the − Δ H ∘ R T −ΔH∘RT term becomes smaller therefore K will get larger.
2. To ensure the dissolution process was at equilibrium.
Explanation:
Given that;
ΔG°= -RTlnK
and
ΔG° = ΔH° - TΔS°
So;
-RTlnK = ΔH° - TΔS°
lnK = ΔH°/-RT - TΔS°/-RT
lnK = -(ΔH°/RT) + ΔS°/R
K = e^-(ΔH°/RT) + ΔS°/R
Hence, Solubility will increase, because as T increases the − Δ H ∘ R T −ΔH∘RT term becomes smaller therefore K will get larger.
2.
Since solubility is an equilibrium process, it means that some undissolved solute must be present in order to determine the solubility product correctly.
