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Anna35 [415]
4 years ago
13

The first-order rate constant for the decomposition of n2o5, 2n2o5(g)→4no2(g)+o2(g) at 70∘c is 6.82×10−3 s−1. suppose we start w

ith 2.00×10−2 mol of n2o5(g) in a volume of 2.3 l . you may want to reference (page) section 14.4 while completing this problem. part a how many moles of n2o5 will remain after 4.0 min ?,
Chemistry
1 answer:
torisob [31]4 years ago
7 0

The rate constant for 1st order reaction is

K = (2.303 /t) log (A0 /A)

Where, k is rate constant

t is time in sec

A0 is initial concentration

(6.82 * 10-3) * 240 = log (0.02 /A)

1.63 = log (0.02 /A)

-1.69 – log A = 1.63

Log A = - 0.069

A = 0.82

Hence, 0.82 mol of A remain after 4 minutes.

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If a disease destroying barley plants in a field swept through an ecosystem, what would happen to the barley eating bird populai
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Answer:

It would decrease

Explanation:

In an ecosystem, organisms feed on one another for survival due to the fact that energy needed for metabolic activities in individual organisms can only be obtained via food. This question depicts that certain bird population feeds on barley plant in an ecosystem.

However, If a disease attacks the plants in such a way that it destroys the barley plants in the field, this would cause the barley-eating bird population to DECREASE because their food source has been affected.

6 0
3 years ago
Material safety data sheets are used to give the information about a solvent. The excerpt below is part of an MSDS. Which inform
Kitty [74]

Answer:

the answer is A

Explanation:

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7 0
3 years ago
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How does the Coriolis effect influence the movement of surface waters?
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Answer:

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3 0
3 years ago
Question 19 Write a balanced half-reaction for the oxidation of gaseous nitrogen dioxide to nitrate ion in acidic aqueous soluti
Alexxx [7]

Answer:

This will be the balanced half reaction:

NO₂(g)  + H₂O (l) →  NO₃⁻(aq)  + 1 e⁻  + 2H⁺ (aq)

Explanation:

In acidic medium, the redox balance has to be done as this way.

As it is an oxidation, we know that oxidation state has increased.

NO₂(g)   →  NO₃⁻(aq)  + 1 e⁻

Nitrogen in NO₂ acts with +4; in the nitrate, N acts with +5

The nitrogen has released 1 electron.

As we are in acidic medium, we must complete with water, in the same side, as we have less oxygens and in the opposite side, with protons to balance the H. This will be the balanced half reaction:

NO₂(g)  + H₂O (l) →  NO₃⁻(aq)  + 1 e⁻  + 2H⁺ (aq)

5 0
3 years ago
The question is below
rodikova [14]
The anode is the electrode where the oxidation occurs.

Cathode is the electrode where the reducction occurs.

Equations:

  Mn(2+) + 2e-  --->  Mn(s)                      Eo = - 1.18 V
2Fe(3+) + 2e-  ----> 2 Fe(2+)                2Eo = + 1.54 V

The electrons flow from the electrode with the lower Eo to the electrode with the higher Eo yielding to a positive voltage.

Eo = 1.54 V - (- 1.18) = 1.54 + 1.18 = 2.72

Answer: 2.72 V

3 0
3 years ago
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