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Sedbober [7]
3 years ago
8

Jeanette grew 12 flowers with 2 seeds packets how many seed packets does jeanntte need to have a total of 18 flowers in the grad

en
Mathematics
2 answers:
insens350 [35]3 years ago
7 0

Answer: 3 packets

12/2 = 6 seeds per packets

18/6 = 3 packets

Vlad [161]3 years ago
7 0

Answer:

3

Step-by-step explanation:

If Jeanette grew 12 flowers with 2 seeds packets, that means that each seed packet grows 6 flower. 12/2=6

If each seed packet grows 6 flowers, 3 seed packets will give 18 flowers. Hope this helps!

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What is the value of the discriminant, b2 − 4ac, for the quadratic equation 0 = x2 − 4x + 5, and what does it mean about the num
forsale [732]
(-4)^2-4(1)(5)
16-4(1)(5)
16-4(5)
16-20
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The discriminant is negative so there are no real number solutions.
3 0
3 years ago
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Mrs. Olga’s $250 investment earns 19% interest compounded annually. What will her balance be after 3 years?
Maurinko [17]

Answer:

The answer is A. $421.29

Step-by-step explanation:

Just keep finding 19% of the numbers next, and you add that all up and you get the answer.

250 x 19%=47.5. (250+47.5)=> 297.5x19%= 56.525. (297.5+56.525) =>354.025x19%=67.26475

354.025+67.26475=> 421.28975, which can round up to 421.29.

6 0
3 years ago
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Determine whether the following problem involves a permutation or combination.​ (It is not necessary to solve the​ problem.) How
Aleksandr [31]

Answer:

Permutation

Step-by-step explanation:

Since we are talking about passwords the order of the letters matters, i.e, the pasword UpT is different to the pasword pUT. Therefore, the problem involves all the permutations of 33 letters, from the given letters, where no repetitions of letters are allowed.

4 0
3 years ago
) Find the coordinates of the point A' which is the symmetric point
soldier1979 [14.2K]

Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point  A(3, 2) with respect to the line 2x + y - 12 = 0.​

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

C( \dfrac{x+3}{2}, \dfrac{y+2}{2})

Also, product of slope will be -1 .( Since, they are parallel )

\dfrac{y-2}{x-3} \times -2  = -1\\\\2y - 4 = x - 3\\\\2y - x = 1

x = 2y - 1

So, C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})

Also, C satisfy given line :

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Also,

x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}

Therefore, the symmetric points isA'(\dfrac{31}{5}, \dfrac{18}{5}) .

7 0
2 years ago
A plant is growing at about 0.45 inches a day. Find the change in the height of the plant after 14 days
Nikitich [7]
About 6.3 inches after 14 day!

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