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inn [45]
3 years ago
8

A square picture in a magazine has an area of 27 square inches. What is the length of each side of the picture?

Mathematics
1 answer:
hodyreva [135]3 years ago
7 0

Answer:

5.19615242271

Step-by-step explanation:

I square root 27 and got 5.19615242271, so that picture is not a perfect square but if you want to be exact that's the answer

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Help!!!!!!!!!!!!!!!!!!!!
natima [27]
Expression: 3⁴ . 2³

= 3 * 3 * 3 * 3 * 2 * 2 * 2

= 81 * 8

= 648

In short, Your Answer would be: 648

Hope this helps!
3 0
3 years ago
Read 2 more answers
Writing an Equation with Two Variables Hugh bought some magazines that cost $3.95 each and some books that cost $8.95 each. He s
makkiz [27]
<span>3.95m + 8.95b = 47.65</span>
6 0
3 years ago
In a science-fiction story, a spaceship travels 3 times faster each minute than it traveled during the minute before. If the shi
JulijaS [17]

The expression is:

speed(minutes)=3\frac{km}{h} ^{minutes} \\\\speed(15minutes)=(3^{15})\frac{km}{4} =14348907\frac{km}{g}

Why?

From the statement we know that the spaceship travels 3 times faster each minute that it traveled during the minute before, it can be expressed using an exponential function, its base will be the starting speed (during the first minute).

The expression will be:

speed(minutes)=(3^{minutes})\frac{km}{h} \\\\speed(15minutes)=(3^{15})\frac{km}{h}=14348907\frac{km}{h}

Have a nice day!

6 0
3 years ago
What’s the gcf of 18k and 15k cubed?
Contact [7]

Answer:

The GCF for the variable part is  

k

Step-by-step explanation:

Since  

18

k

,

15

k

3

contain both numbers and variables, there are two steps to find the GCF (HCF). Find GCF for the numeric part then find GCF for the variable part.

Steps to find the GCF for  

18

k

,

15

k

3

:

1. Find the GCF for the numerical part  

18

,

15

2. Find the GCF for the variable part  

k

1

,

k

3

3. Multiply the values together

Find the common factors for the numerical part:

18

,

15

The factors for  

18

are  

1

,

2

,

3

,

6

,

9

,

18

.

Tap for more steps...

1

,

2

,

3

,

6

,

9

,

18

The factors for  

15

are  

1

,

3

,

5

,

15

.

Tap for more steps...

1

,

3

,

5

,

15

List all the factors for  

18

,

15

to find the common factors.

18

:  

1

,

2

,

3

,

6

,

9

,

18

15

:  

1

,

3

,

5

,

15

The common factors for  

18

,

15

are  

1

,

3

.

1

,

3

The GCF for the numerical part is  

3

.

GCF

Numerical

=

3

Next, find the common factors for the variable part:

k

,

k

3

The factor for  

k

1

is  

k

itself.

k

The factors for  

k

3

are  

k

⋅

k

⋅

k

.

k

⋅

k

⋅

k

List all the factors for  

k

1

,

k

3

to find the common factors.

k

1

=

k

k

3

=

k

⋅

k

⋅

k

The common factor for the variables  

k

1

,

k

3

is  

k

.

k

The GCF for the variable part is  

k

.

GCF

Variable

=

k

Multiply the GCF of the numerical part  

3

and the GCF of the variable part  

k

.

3

k

3 0
3 years ago
The length of a park is 250 meters. What is the length of the park in kilometers
Tatiana [17]
0.25 kilometers
Using the universal measurement
Kilo, hecto, deca, unit, deci, centi, milli
Kilometer, hectometer, decameter, meter, decimeter, centimeter, millimeter

From unit you would move three time to the left from your decimal point on your starting number 250. You would move it three times to the left because meter to kilometer is three decimals to the left

A way I remember my universal measurements is king (k-kilo), Henry (h-hecto), died (d-deca), unexpectedly (u-unit as in liters, meters, grams) drinking (d-deci), chocolate (c-centi) milk (m-milli)
4 0
4 years ago
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