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Murljashka [212]
3 years ago
5

Are the given values in the table enough information to show an exponential function instead of a linear function? If not, expla

in why not then write the equations for both an exponential and linear function represented by the table.

Mathematics
1 answer:
baherus [9]3 years ago
3 0

Step-by-step explanation:

Are the given values in the table enough information to show an exponential function instead of a linear function? If not, explain why not then write the equations for both an exponential and linear function represented by the table.

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Solve the system of linear equations by substitution.<br><br> x=2y+7<br> 3x−2y=3
Murljashka [212]
<u>The system of equation</u>
First equation
x = 2y + 7
Second equation
3x - 2y = 3

<u>Substitute x with (2y + 7) in the second equation</u>
3x - 2y = 3
3(2y + 7) - 2y = 3

use distributive property
3(2y) + 3(7) - 2y = 3
6y + 21 - 2y = 3

add like terms
6y - 2y + 21 = 3
4y = 3 - 21
4y = -18
  y = -18/4
  y = -4.5

<u>Substitute y with its value, which is -4.5, in the first equation</u>
x = 2y + 7
x = 2(-4.5) + 7
x = -9 + 7
x = -2

<u>The solution is</u>
<u />(x,y) = (-2, -4.5)
6 0
4 years ago
Plssssssss help
Dvinal [7]
The correct answer is B
6 0
3 years ago
Hey does any body know how i can approximate 13 like this had this homework but it got late on me.​
Illusion [34]

Answer:

(see attachment)

To approximate the square root of 13:

Working from the top down...

Enter the number you are trying to approximate in the top box: \boxed{\sf \sqrt{13}}

Find the perfect squares directly below and above 13.

Perfect squares:  1, 4, 9, 16, 25, 36, ...

Therefore, the perfect squares below and above 13 are: 9 and 16

Enter these with square root signs in the next two boxes: \boxed{\sf \sqrt{9}} and  \boxed{\sf \sqrt{16}}  

Carry out the operation and enter  \boxed{\sf 3} and \boxed{\sf 4} in the next two boxes.

Enter the number you are trying to square root (13) in the top left box, the perfect square above it (16) in the box below, then the perfect square below it (9) in the two boxes to the right of these. Carry out the subtractions and place the numbers in the boxes to the right.

\dfrac{\boxed{\sf 13}-\boxed{\sf 9}}{\boxed{\sf 16}-\boxed{\sf 9}}=\dfrac{\boxed{\sf 4}}{\boxed{\sf 7}}

Now enter the number you are trying to square root (13) under the square root sign.  Place the square root of the perfect square below it (3) in the box to the right.  Copy the fraction from above (4/7).  Finally, enter this mixed number into a calculator and round to the nearest hundredth.

\sf \sqrt{13}=\boxed{\sf3}\dfrac{\boxed{\sf 4}}{\boxed{\sf 7}}=\boxed{\sf3.57}

7 0
2 years ago
What is the answer -1x-4&gt;10
ser-zykov [4K]

Answer:

1x>-14

Step-by-step explanation:

-1x-4>10

move constant to right

-1x>10+4

add 10 and 4

-1x>14

move negative sign to other side

1x>-14

7 0
3 years ago
Please help with this problem ,<br> what is 5 x 6
-BARSIC- [3]

Answer:

the answer is 30

8 0
3 years ago
Read 2 more answers
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