3 years ago

Can someone help me pls

Mathematics

1 answer:

Hunter-Best [27]3 years ago

4 0

Answer:

New York is a nice place

Step-by-step explanation:

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Determine the modulus of each of the complex numbers in the matching pairs. List these moduli in order from smallest to largest.

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Answer:

the modulus of a complex number z = a + bi is:

Izl= √(a²+b²)

The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:

m = 2 + 6i

n = a + bi

Im + nl = 3√10

√(a² + b²+ 2²+ 6²)= 3√10

√(a^2 + b^2 + 40) = 3√10

squaring both side

a²+b²+40 = 3^2*10 = 9*10 =90

a²+b²= 90 - 40

a²+b²=50

So,

|n|=√(a^2 + b^2) = √50

The modulus of n must be equal to the square root of 50.

now

values a and b such

a^2 + b^2 = 50.

for example, a = 5 and b = 5

5²+5²=25+25= 50

Then a possible value for n is:

n = 5+5i

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used,Consider the functions given below.P(x) =

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Solution

we are given

$\begin{gathered} P(x)=\frac{2}{3x-1} \\ Q(x)=\frac{6}{-3x+2} \end{gathered}$

(a). P(x) / Q(x)

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(b). P(x) x Q(x)

$\begin{gathered} P(x)\cdot Q(x)=\frac{2}{3x-1}\times\frac{6}{-3x+2} \\ P(x)\cdot Q(x)=\frac{12}{(3x-1)(-3x+2)} \end{gathered}$

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$42 \frac{5}{10} + 37 \frac{8}{10}$

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