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Dafna1 [17]
3 years ago
15

Louis is a gardener. He plants 5 rose bushes for every 2 lilac bushes. If Louis plants 25 rose bushes, how many lilac bushes doe

s he plant ?
Mathematics
1 answer:
kenny6666 [7]3 years ago
4 0
Oh, this is a fun one.
25/5=5.
5*2=10
He plants 10 lilac bushes. 
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Jenny makes food for her hummingbird feeders. The food is made up of 1 part sugar and 4 parts water. She uses 3434 cup of sugar
Bond [772]
Okay so every part of sugar requires 4 parts of water 

so

3434 cups of sugar x 4 (parts of water per 1 part of sugar) = 13736 

She will need to use 13, 736 parts of water for 3, 434 parts of sugar 
5 0
3 years ago
Read 2 more answers
Question:<br> 15-4+ (7 - 5)
GREYUIT [131]

Answer:

13

Step-by-step explanation:

15 - 4 + 7 - 5 = 13

Simply expand the brackets and subtract and add accordingly.

3 0
2 years ago
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Evaluate the expression for x = 3 y= 1/3 and z= 5. 12 x - 3y / 4 x - Z​
4vir4ik [10]

Answer:

5

Step-by-step explanation:

12 x - 3y / 4 x - Z

=12×3-3×1/3÷4×3-5

=36-1/12-5

=35/7

=5

So the final answer is 5.

5 0
3 years ago
If a fair coin is tossed, the probability that it will land heads up is ½. Olivia tosses a coin 4 times, and it lands on heads 4
disa [49]

Answer:

C

Step-by-step explanation:

The tosses before that were all by chance, the probability is still the same. Nothing changes.

6 0
3 years ago
WILL MARK BRAINLIEST
Levart [38]

Answer:

Part 1:

The solution set of the system of equations is x = 1, y = 1

Part 2:

The solution set is x = 1, y = 1

Part 3:

The similarity of the system of equations in Parts 1 and 2 is that they have the same solution set

The difference of the system of equations in Parts 1 and 2 is that they are arranged differently

Step-by-step explanation:

Part 1:

The system of equation is given as follows;

2·x + y = 3...(1)

x = 2·y - 1...(2)

The above system of equations can be written in terms of the variable, y, as follows;

For equation (1), we have;

y = 3 - 2·x

For equation (2), we have;

y = (x + 1)/2

From the attached graph created with Microsoft Excel, we have;

The solution set (the point of intersection) of the system of equations is x = 1, y = 1

To accurately find the common solution, we have;

(x + 1)/2 = 3 - 2·x

x + 1 = 2·(3 - 2·x) = 6 - 4·x

x + 1 = 6 - 4·x

x + 4·x = 6 - 1

5·x = 5

x = 5/5 = 1

x = 1

Therefore, y = 3 - 2·x = 3 - 2× 1 = 1, at the common solution

Part 2:

y = -2x + 3

x - 2y = -1

∴ x = 2y -1

y = -2(2y -1) + 3

y = -4y + 2 + 3

5y = 5

y = 1

x = 2y - 1 = 2 - 1 = 1

x = 1

The solution set is x = 1, y = 1

Part 3

The system of equations are similar in terms of their solution

The system of equations are different in terms of their arrangement

6 0
2 years ago
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