Let ∠RTS=∠RST = a (say)
∠QUA=∠QSU= b(say)
then we know , at point S, a+40+b=180. so, a+b=140 we'll use this later.
consider trianglePQR, ∠P+∠Q+∠R=180
i.e.P+(180-2b)+(180-2a)=180
P+180+180-2(a+b)=180 ⇒P+180-2(a+b)=0 ⇒P=2(140)- 180=280-180=100
hence,answer is E
Answer:
C: ∠6 and ∠2
Step-by-step explanation:
Step 1:
∠6 = ∠9 S.S. Int. ∠'s (Same Side Interior ∠'s)
Step 2:
∠9 + ∠2 = 180° Sum of line
Step 3:
∠9 ≠ ∠2
Answer:
C: ∠6 and ∠2
Hope This Helps :)
Answer:
its B
Step-by-step explanation:
have a great day my man
