The area enclosed by the figure is 4533.48 square meters.
<u>Step-by-step explanation:</u>
Side length of the square = 42m
The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.
Radius of the semicircle = 21m
Area of the square = 42 x 42 = 1764 square meters
Area of 1 semicircle = π(21 x 21) /2
= (3.14) (441) /2
= 1384.74/2
= 692.37 square meters
Area of 4 semicircle = 4 x 692.37
= 2769.48 square meters
Total area = 1764 + 2769.48
= 4533.48 square meters
The area enclosed by the figure is 4533.48 square meters.
They’re all the same answer so...??
300/250 can be divide by 50 which makes it 6/5
Answer:
The value of x is 3
Step-by-step explanation:
∵ Quadrilateral ABCD is congruent to quadrilateral JKLM
∴ AB = JK and BC = KL
∴ CD = LM and AD = JM
∵ BC = 8x + 7
∵ KL = 31
∵ BC = KL
→ Equate their right sides
∴ 8x + 7 = 31
→ Subtract 7 from both sides
∵ 8x + 7 - 7 = 31 - 7
∴ 8x = 24
→ Divide both sides by 8 to find x
∴ 
= 
∴ x = 3
∴ The value of x is 3
Let x = the number of alternative schools.
Therefore, 2x - 4 = 48.
2x -4 +4 = 48 + 4
2x = 52
x = 26
Therefore, there are 26 alternative schools(You could check this answer by substituting x=26 into the equation above.).
