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makvit [3.9K]
3 years ago
11

Lindsey is tracking the progress of her plant’s growth. Today the plan is 5cm high. The plant grows 1.5 cm per day. What will th

e height of the plant be after 20 days?
Mathematics
2 answers:
sveta [45]3 years ago
5 0
31.5cm Multiply 20 times 5 then add 1.5 cm because there are 20 days and the plan is to get to 5cm high. The plan only grows 1.5cm per day so 31.5cm would be ur answer
rjkz [21]3 years ago
4 0

31.5 cm . multiply 20 times 5 then added the 1.5 cm

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iogann1982 [59]
Degree is the value of the highest power of the variable, and hence in this case is 8
6 0
3 years ago
Find the zero of each function and state the multiplicity of each zero. Please show all steps.
vodka [1.7K]

Answer:

1. y=(x+3)^3. Zero: x=-3 multiplicity 3.

2. y=(x-2)^2 (x-1). Zeros: x=2 multiplicity 2; x=1 multiplicity 1.

3. y=(2x+3)(x-1)^2. Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.


Step-by-step explanation:

1. y=(x+3)^3

y=0\\ (x+3)^3=0\\ \sqrt[3]{(x+3)^3}=\sqrt[3]{0}\\ x+3=0\\ x+3-3=0-3\\ x=-3

Zero: x=-3 multiplicity 3.


2. y=(x-2)^2 (x-1)

y=0\\ (x-2)^2(x-1)=0\\ \left \{ {{(x-2)^2=0} \atop {x-1=0}} \right\\ \left \{ {{\sqrt{(x-2)^2} =\sqrt{0} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x-2=0} \atop {x=1}} \right\\ \left \{ {{x-2+2=0+2} \atop {x=1}} \right\\ \left \{ {{x=2} \atop {x=1}} \right.

Zeros: x=2 multiplicity 2; x=1 multiplicity 1


3. y=(2x+3)(x-1)^2

y=0\\ (2x+3)(x-1)^2=0\\ \left \{ {{2x+3=0} \atop {(x-1)^2=0}} \right\\ \left \{ {{2x+3-3=0-3} \atop {\sqrt{(x-1)^2} =\sqrt{0} }} \right\\ \left \{ {{2x=-3} \atop {x-1=0}} \right\\ \left \{ {{\frac{2x}{2} =\frac{-3}{2} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x=-\frac{3}{2} } \atop {x=1}} \right.

Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.

4 0
3 years ago
Simplify using laws of exponents: 5^7 × 5^6 × 52
xxMikexx [17]

\displaystyle \rm 5 ^{7}  \times 5 ^{6}  \times 52

\displaystyle \rm \: 5 ^{7 + 6}  \times 52

\displaystyle \rm \: 5 ^{13}  \times 52

\tt \: 63476562500

5 0
3 years ago
Find all points having an x-coordinate of 5 whose distance from the point (2, 6) is 5
galina1969 [7]

Answer:

(5,2) and (5,10)

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

points\ (2,6),(5,y)\\d=5

substitute in the formula

5=\sqrt{(y-6)^{2}+(5-2)^{2}}

solve for y

5=\sqrt{(y-6)^{2}+(3)^{2}}

5=\sqrt{(y-6)^{2}+9}

square both sides

25=(y-6)^{2}+9

(y-6)^{2}=25-9

(y-6)^{2}=16

square root both sides

y-6=\pm4

y=6\pm4

y=6+4=10

y=6-4=2

therefore

The points are

(5,2) and (5,10)

6 0
3 years ago
A company's year-end data shows the following amounts. Current assets $65,000 Current liabilities $25,000 Net income $7,500 Net
lozanna [386]

The company's current ratio is 2.6.

<h3>What is the current ratio?</h3>

Current ratio is an example of a liquidity ratio. Liquidity ratios are financial ratios measure a firm's ability to honour its short terms obligations.

Current ratio = current asset /current liability

$65,000 / 25,000 = 2.6

To learn more about current ratio, please check: brainly.com/question/19579866

#SPJ1

4 0
2 years ago
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