China was isolated because of

If you had $9 what would you buy

Karolina [17]

Answer:

Food

Step-by-step explanation:

You need food to survive so find some good food and eat it :)

4 0

3 years ago

Read 2 more answers

A student has 10 coins in her pocket that have a value of 0.85,The coins are either nickels of dimes. Which system of linear equ

oee [108]

Answer:

p+q = 10...... 1

0.05p+0.10q = 0.85 ..... 2

Step-by-step explanation:

The question is incomplete. Here is the complete question.

A student has 10 coins in her pocket that have a value of $0.85. The coins are either nickels or dimes. If each nickel costs $0.05 and each dime costs $0.10. Which system of linear equations represents this scenario?

Let the number of nickel in the pocket of the student be p

Let the number of dime in the pocket of the student be q

If there are 10 coins in her pocket, then the total coins in her pocket will be represented by the equation;

p+q = 10...... 1

If each nickel costs $0.05, p nickels will cost $0.05×p = $0.05p

If each dime costs $0.10, q nickel will costs $0.10×q = $0.10q

Total amount will be $0.05p+$0.10q

Now if the total coins in her pocket has a value of $0.85, then the we will equate $0.05p+$0.10q to $0.85 to give our second linear equation as:

$0.05p+$0.10q = $0.85 ....... 2

Therefore, the system of linear equations represents this scenario are:

p+q = 10...... 1

0.05p+0.10q = 0.85 ..... 2

7 0

3 years ago

Find the intersection points using substitution or elimination for each system of equations:

natka813 [3]

Answer:

Step-by-step explanation:

Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.

Problem 1:

(x²)/4 +y²= 1

y= x+1

*substitute for y*

Now we have a one-variable equation we can solve-

x²/4 + (x+1)² = 1

x²/4 + (x+1)(x+1)= 1

x²/4 + x²+2x+1= 1

*subtract 1 from both sides to set equal to 0*

x²/4 +x^2+2x=0

x²/4 can also be 1/4 * x²

1/4 * x² +1*x² +2x = 0

*combine like terms*

5/4 * x^2+2x+ 0 =0

now, you can use the quadratic equation to solve for x

a= 5/4

b= 2

c=0

the syntax on this will be rough, but I'll do my best...

x= (-b ± √(b²-4ac))/(2a)

x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))

x= (-2 ±√(4-0))/(2.5)

x= (-2±2)/2.5

x will have 2 answers because of ±

x= 0 or x= 1.6

now plug that back into one of the equations and solve.

y= 0+1 = 1

y= 1.6+1= 2.6

Hopefully this explanation was enough to help you solve problem 2.

Problem 2:

x² + y² -16y +39= 0

y²- x² -9= 0

6 0

3 years ago

If the entire school had 720 students can use this data to estimate how many of them would say that it takes them more than 10 m

Law Incorporation [45]

Answer:

I don't know but this question feels incomplete

7 0

3 years ago

Identify the scale factor.

Xelga [282]

Answer:

3

Step-by-step explanation:

5 0

3 years ago

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