Miriam buys 24 petunia plants and 40 azalea plants
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Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then
By substitution, we have that
and 
.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
By substitution, we have that
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
<h3>Answer :</h3>
<u>Given</u> :
- 9(m + 5) - 3(m - 2) = 8m + 31
We have to find value of m
➠ 9(m + 5) - 3(m - 2) = 8m + 31
➠ 9m + 45 - 3m + 6 = 8m + 31
➠ 9m - 3m + 45 + 6 = 8m + 31
➠ 6m + 51 = 8m + 31
➠ 51 - 31 = 8m - 6m
➠ 20 = 2m
➠ m = 20/2
➠<u> m = 10</u>
<h3>Hope It Helps!</h3>