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podryga [215]
4 years ago
7

In a given rectangle, the longer sides are 7 units longer than the shorter sides. If we let the shorter sides be represented as

x, write an expression below that represents the perimeter.
A
2x + 7

B
4x2 + 49

C
4x + 49

D
4x + 14
Mathematics
2 answers:
Goryan [66]4 years ago
7 0

Answer:

Option D 4x+14

Step-by-step explanation:

Given: The longer sides are 7 units longer than the shorter sides. The shorter side is x.

To find: Write an expression below that represents the perimeter.

Solution: It is given that the shorter side is x.

The longer side is 7 units longer than the shorter side. So, the longer side is x+7

We know that the perimeter of the rectangle is 2(\text{length}+\text{breadth})

So, the expression for the perimeter

=2(x+x+7)

=2(2x+7)

=4x+14

Hence, the expression for perimeter is 4x+14.

So, option D is correct.

strojnjashka [21]4 years ago
6 0

Answer: D because the two longer sides are 7 unites longer, meaning you need to add 14 (7x2) to the final product

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Answer:

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Step-by-step explanation:

what you pick, p , plus the 14 you have, must be less than the 50 allowed.

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Simplify completely..........​
vitfil [10]

Answer:

\frac{x}{x-1}

Step-by-step explanation:

\frac{3x^2 - 1}{x^2 - 1} - \frac{2x + 1}{x + 1}                                          [ \ x^ 2- 1 = (x-1)(x + 1) \ ]

= \frac{3x^2 - 1}{(x-1)(x  + 1 )} - \frac{2x + 1}{x + 1}\\\\=\frac{(3x^2 - 1)-(2x + 1)(x-1)}{(x + 1)(x-1)}                        [\ Taking \ LCM \  ]

= \frac{(3x^2 - 1)- (2x^2 - 2x + x - 1)}{(x+1)(x-1)}\\\\=\frac{3x^2 - 1 - 2x^2 + x + 1 }{(x+1)(x-1)}\\\\=\frac{x^2 +x}{(x+1)(x-1)}\\\\=\frac{x(x+1)}{(x+1)(x-1)}\\\\=\frac{x}{x-1}

<em><u>Finding LCM :</u></em>

Example :

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6 = 2  x   3

3 = 1   x   3

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[ To make the denominators same : the second fraction is multiplied and divided by 2 ]

Similarly :

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Same rule we applied : multiplied the numerator and denominator of the second term with ( x - 1 )

Therefore the second term becomes ,

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