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zalisa [80]
3 years ago
6

A father gave 1/6 of his money to his daughter and gave 1/5 of the remaining to his son and the father was left with $600. Whats

the total amount of money he gave to his children?

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
5 0
Assume x is the total amount.
x = 1/6 x + (x - 1/6 x)1/5 + 600
x = 1/6 x + 1/5 x - 1/30 x + 600
x = 5/30 x + 6/30 x - 1/30 x + 600
x = 10/30 x +600
3/3 x - 1/3 x = 600
x = 600*3/2 = $900

Good luck
adoni [48]3 years ago
4 0
*void photo*

Assume M is the Total Money

M/6 + (1/5)(M - M/6) + $600 = M

M/6 + M/5 - M/30 + $ 600 = M

M/6 + M/5 - M/30 - M = -$600

(1/6 + 1/5 - 1/30 - 1)M = -$600

-2M/3 = -$600

2M/3 = $600

M = ($600)(3/2)

M = $900

so the total money is $900
but the money he gave to his children is only 1/3 of the Total Money(M)

therefore,
=(1/3)($900)
=$300

$300 is the total money he gave to his children

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\large\boxed{f(4)=-1292}

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f(n)=-5f(n-1)-2\\\\f(1)=10\\\\f(2)=-5f(2-1)-2=-5f(1)-2\\\text{put}\ f(1)=10:\\f(2)=-5(10)-2=-50-2=-52\\\\f(3)=-5f(3-1)-2=-5f(2)-2\\\text{put}\ f(2)=-52\\f(3)=-5(-52)-2=260-2=258\\\\f(4)=-5f(4-1)-2=-5f(3)-2\\\text{put}\ f(3)=258\\f(4)=-5(258)-2=-1290-2=-1292

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