Ask question

Ask question

All categories

3 years ago

5

What is the value of the expression below when z =5 and w=5? 9z-3w

2 answers:

zysi [14]3 years ago

7 0

This is just about substitution!! 9(5)-3(5), 3 • 5 = 15
9 • 5 = 45
so Now you have, 45 - 15 = 30

soldier1979 [14.2K]3 years ago

7 0

Answer:

= 30

Step-by-step explanation:

9z-3w

9(5)-3(5)

Multiply:

45-3(5)

Multiply:

45-15

Subtract:

= 30

You might be interested in

Find an equation for the line parallel to 3y+6X=6 and goes through the point (-3,-7) please write in y=mx+b

seropon [69]

Answer: y=-6x-25

Step-by-step explanation:

Find slope of original line by solving for y

3y+6x=6

y+6x=2

y = -6x+2 <--- we have found the slope is -6

Using y-y1 = m (x-x1) find the equation for the parallel line:

y-(-7)= -6(x-(-3)) <--- plug in the point coordinates and slope into the equation and solve for y

y+7=-6x-18

y=-6x-25

5 0

2 years ago

Can someone help me answer this question ( moderators this is not a copy, the other ones got erased so go away)

Rainbow [258]

Triangles ABC and ADE are similar triangles. That means the sides are all scaled by the same factor.

To go from side BC to side DE, you multiply by 1.25. That means 1.25 is your scale factor. Now apply that factor to the bottom side to get your answer.

Side AB is 6. That means side AD is 6 x 1.25 = 7.5. That means x = 7.5 - 6 = 1.5

6 0

3 years ago

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

4 0

3 years ago

Read 2 more answers

in a random School sampling of 50 middle school students it was found that 18 students bring their lunch to school everyday if t

dem82 [27]

Answer:

340

Step-by-step explanation:

We can see in the sample that 18/50 people bring lunches to school. If we divide 18 by 50 we get 0.36 now we know that 36% of people bring their lunches in the sample. Now we take that number and multiply it by 942.

0.36*942= 339.12 which we can round to 340

5 0

2 years ago

Use the dropdown menus to write an equation with infinitely many solutions.

nika2105 [10]

Answer:

4(2x + 3) - x = 7x + 12

Explanation:

That's what T4L/Edge said

8 0

3 years ago