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2 years ago

What is the value of the expression below when z =5 and w=5? 9z-3w

Mathematics

2 answers:

zysi [14]2 years ago

7 0

This is just about substitution!! 9(5)-3(5), 3 • 5 = 15
9 • 5 = 45
so Now you have, 45 - 15 = 30

soldier1979 [14.2K]2 years ago

7 0

Answer:

= 30

Step-by-step explanation:

9z-3w

9(5)-3(5)

Multiply:

45-3(5)

Multiply:

45-15

Subtract:

= 30

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Answer:

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Step-by-step explanation:

3 0

2 years ago

Literal equations 2x-3y=8 solve for y

vichka [17]

2x-3y = 8

Add 3y on both sides

2x = 8 + 3y

Subtract 8 on both sides

3y = 2x - 8

Divide 3 on both sides

$y= \frac{2}{3}x- \frac{8}{3}$

4 0

3 years ago

Read 2 more answers

HELP ME IM STUCK ANSWER IT QUICK

fiasKO [112]

Answer:

red = 28 apples

green = 13 apples

equations:

r + g = 41

r = g + 15

Step-by-step explanation:

r = number of red

g = number of green

r = g + 15 (the number of red apples is 15 more than the number of green apples)

r + g = 41

Substitute the firs equation into the second and solve for a numerical value of g

(g + 15) + g = 41

2g + 15 = 41

2g = 26

g = 13

Now solve for a numerical value of r

r = g + 15

r = 13 + 15

r = 28

checking the math:

r + g = 41

28 + 13 = 41

Please lmk if you have any questions.

6 0

2 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$