Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
240 meters^2
Step-by-step explanation:
Area of a triangle is 1/2b*h. (b=base, h=height). To solve you plug in the values 30 as b and 16 as h and then multiply to get 240.
Answer:
whats the question?
Step-by-step explanation:
have a good day!!!
(PS or is this just a tip?)
Answer:
not telling u, imbecil
Step-by-step explanation:
hahhahahahah
