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2 years ago

Solve the quadratic equation for x. (x−4)(x+6)=0

Mathematics

2 answers:

Rufina [12.5K]2 years ago

8 0

Answer:

X = 4, -6

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

maksim [4K]2 years ago

5 0

Answer:

x = 4 and x = -6

Step-by-step explanation:

We can use the Zero Identity Property, which states that 0 * n = 0, where n is any number.

Here, in order for (x - 4)(x + 6) = 0 to be true, either x - 4 must equal 0 or x + 6 must equal 0. So set each of them equal to 0 and solve for x:

x - 4 = 0

x = 4

x + 6 = 0

x = -6

The answers are x = 4 and x = -6.

Hope this helps!

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2 years ago

Solve using the quadratic formula 3x^2+11x+5=0

storchak [24]

Answer:

$3x^2 + 11x + 5 = 0 : x = \frac{-11 + \sqrt{61} }{6} , x = \frac{-11 - \sqrt{61} }{6}$

Decimal:

$(x = -0.53162..., x = -3.13504...)$

Step-by-step explanation:

$3x^2+11x+5=0$

Solve with the quadratic formula:

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are:

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

For $a=3,\:b=11,\:c=5:\quad x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}$

$x=\frac{-11 + \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 + \sqrt{61} }{6}$

$x=\frac{-11 - \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 - \sqrt{61} }{6}$

The solutions to the quadratic equation are:

$x=\frac{-11+\sqrt{61}}{6},\:x=\frac{-11-\sqrt{61}}{6}$

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

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Answer:

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Step-by-step explanation:

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See the attachment for detailed answer
<span>So then R is 1/6 of the way from E to F.
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