I would add like terms, meaning subtract 6.4 from both sides.
3.5n = 36.1
From the graph, when x = 1, y = 57,000.
Replace x with 1 in the equations and see if any of the Y 's equal 57,000 :
y = -2610.82(1) + 47860.82 = 45,250
y = 219(1)^2 - 6,506.78(1) + 59,385 = 219 - 6506.78 + 59385 = 53,097.22
y = 54041.5(0.9)^1 = 48,637.35
y = 10,504.6 (1.1)^1 = 11,555.06
The second equation is the closest. so try another x value to see if it is close to the Y value:
Let's try x = 14:
y = 219(14)^2 - 6506.78(14) + 59,385 = 42924 - 91094.92 + 59385 = 11,214.08
This is close to Y = 12,00 shown on the graph
SO the closest equitation is y = 219x^2 - 6506.78x + 59385
Given data:
The first point given iis (a, b)=(-6,2).
The second point given is (c,d)=(0, -6).
The expression for the slope is,
m=(d-b)/(c-a)
Substitute the given points in the above expression.
m=(-6-2)/(0-(-6))
=(-8)/(6)
=-4/3
Thus, the slope of the line is -4/3, so (C) option is correct.
We need to divide for this. Since there are 12 months in a year, we divide his yearly salary by 12.
270,920.64÷12=22,576.72
So, Mr.Castillo's monthly salary is $22,576.72.
Take 3 out of both of them
3(5x+2)
