Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
Answer:
<em>C. 1/(4^10)</em>
Step-by-step explanation:
<h2>Let's break it down: 4^-2 = 1/(4^2)</h2><h2>(1/(4^2))^5 = (1^5)/(4^2)^5 = 1/(4^10)</h2>
Answer:
A
Step-by-step explanation:
Hope this helps
1) Convert the mixed number 8 and 2/13 into a fraction:
8 and 2/13 = 8 + 2/13 = (8*13 + 2) / 13 = 106 / 13
2) Calculate 4/5 of 106 / 13
(4 / 5) * ( 106 / 13) = (4*106) / (5*13) = 424 / 65
That is (390 + 34) / 65 = 390/65 + 34/65 = 6 + 34/65 is painted white
3) Calculate the rest
(1/5) * (106 / 13) = 106 / 65 = 1 + 41/65 is painted blue
Answer:

Step-by-step explanation:
We know that the volume of a cone:-

(r = 10) (h = 6)

<u>Divide numbers:-</u>



<u>Multiply numbers:-</u>

Therefore, your answer is 200π³
We could also multiply 200 by 3.14 which will give you 628 units³.