Your answer would be A because none of the others make sense, Hope that helps!
Answer:
50%
Explanation:
Glucose is a simple sugar with a total of 6 carbon atoms in its structure. Pyruvate has a total of three carbon atoms. Two molecules of pyruvate are obtained per glucose by glycolysis. None of the carbon of glucose is released in the form of CO2 during glycolysis. Therefore, the radio-labeled C-1 of glucose will be the component of the carbon skeleton of one of the total of two pyruvate molecules produced during glycolysis. So, 50% of the pyruvate will exhibit radioactivity.
<span>It would increase the water extraction due to the counter current multiplier system.</span>
The answer your looking for is c hope it helps
and #rateme