Question

When the following quadratic equation is written in general form, what is the value of "c"?

Answer 1

Answer:

The value of c is -8

Step-by-step explanation:

Given

$\frac{-3}{4} x^2 + 2 = 0$

Required

The value of c, when written in a general form.

The general form of a quadratic equation is written as ax² + bx + c = 0

To get the general form of $\frac{-3}{4} x^2 + 2 = 0$, we start by converting the fraction to whole number.

This is done by multiplying both sides of the equation by the denominator of the fraction (4)

Multiply through by 4; This gives us

$4 * \frac{-3}{4} x^2 + 4 * 2 = 4 * 0$

$-3x^2 + 8 = 0$

From the general form of a quadratic equation, ax² + bx + c = 0 , it'll be observed that a is positive and by comparison a = -3 (in $-3x^2 + 8 = 0$)

So, we have to convert -3 to a positive integer by multiplying both sides of the equation by -1. This gives

$-1 * -3x^2 + -1 * 8 = -1 * 0$

$3x^2 - 8 = 0$

Writing $3x^2 - 8 = 0$ in a more general form, we have

$3x^2 + 0x - 8 = 0$

By comparing ax² + bx + c = 0  to $3x^2 + 0x - 8 = 0$

a = 3

b = 0

c = -8

Hence, the value of c is -8