Yes, 104.12 is greater than 104.002
because 104.12 rounds up to 104.1
and 104.002 rounds up to 104.0
Answer:
E(Y) = $0.5
Var(Y) = 14.25
you should pay the same amount $0.5
Step-by-step explanation:
E(Y) = = Σ(YP)
P = probability of each outcomes.
Var(Y) = Σ
p − (μ x μ)
E(Y) = (2 x 0.25) +(6 x 0.25) + (0.5 x (-3)) = $0.5
Var(Y) = (
x 0.25) + (
x 0.25) +(
x 0.5) - (
)
= 14.5 - 0.25
Var(Y) = 14.25
for the difference between the payoff and cost of playing to have mean 0, you should pay the same amount $0.5
I think is inside and then outside. Not sure
Hope this helps!
The next value would be 48. The values keep increasing by odd numbers. Like the first one is 3 then it goes to 5.
3, 5, 7, 9, 11, 13.....