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mafiozo [28]
3 years ago
15

a can of paint will cover 108 square feet. How many cans of paint are needed to paint a wall 6 feet high and 75 feet long?

Mathematics
1 answer:
AlladinOne [14]3 years ago
4 0
4.166 cans !
6*75 = 450 sq.ft
so approximately 4.166 cans will be required !
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Gus and Ike carried a total of 84 books to the library. If Gus carried 5 as many books as Ike, how many books did they each carr
Alexus [3.1K]

Answer:

They each carried 25 books each.

Step-by-step explanation:

You get this by doing

84/5=16.8

then you do

84/2/5= 8.4

8.4+16.8=25.2

but round to whatever 5 or higher bump up below 5 keep the same

so your answer results in 25.

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47.5%

Step-by-step explanation:

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25 Points ! Write a paragraph proof.<br> Given: ∠T and ∠V are right angles.<br> Prove: ∆TUW ∆VWU
vladimir2022 [97]

Answer:

Δ TUW ≅ ΔVWU ⇒ by AAS case

Step-by-step explanation:

* Lets revise the cases of congruent for triangles

- SSS  ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and  

 including angle in the 2nd Δ  

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ  

 ≅ 2 angles and the side whose joining them in the 2nd Δ  

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

 and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

 leg of the 2nd right angle Δ

* Lets solve the problem

- There are two triangles TUW and VWU

- ∠T and ∠V are right angles

- LINE TW is parallel to line VU

∵ TW // VU and UW is a transversal

∴ m∠VUW = m∠TWU ⇒ alternate angles (Z shape)

- Now we have in the two triangles two pairs of angle equal each

 other and one common side, so we can use the case AAS

- In Δ TUW and ΔVWU

∵ m∠T = m∠V ⇒ given (right angles)

∵ m∠TWU = m∠VUW ⇒ proved

∵ UW = WU ⇒ (common side in the 2 Δ)

∴ Δ TUW ≅ ΔVWU ⇒ by AAS case

7 0
3 years ago
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Answer:

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Step-by-step explanatio



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