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devlian [24]
2 years ago
11

A music Store buys Instruments and then sells them for 30% more than they paid if the store buys a guitar for $45 what will the

store sell it for
Mathematics
2 answers:
VikaD [51]2 years ago
5 0
45$
100+30=130
Then you divide by 100
130 divided by 100= 1.30
Then you multiply 45x1.30=58.50 that’s your answer
Cloud [144]2 years ago
3 0

Answer:

$58.5

Step-by-step explanation:

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skad [1K]

Answer:

hello

Step-by-step explanation:

adjacent angles are equal to 180 degrees,

(2x + 9) + (5x + 3) = 180 \\   8x + 12 = 180 \\ 8x = 180 - 12 \\ 8x = 168 \\ x  =  \frac{168}{8}  \\ x = 21  \\  \\

but, for some reason, does not match the answers…

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7 0
3 years ago
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(01.05) Jacob has four cabin bags. He wants to determine which cabin bag is the heaviest. The actual mass of the cabin bags is s
Lesechka [4]
It would be bad A because when you round to the nearest tenth bags B,C, and D weigh 5.6kg while bag A weighs 5.7kg.
4 0
3 years ago
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㏒7 41 pLz hElP pLZZz
bija089 [108]

Answer:

log(41)/log(7) OR 1.90839852...

4 0
3 years ago
What is 1.995 times 10 to the negative 23
DaniilM [7]
When you say to the -23 do you mean  to the power of?
8 0
3 years ago
Basil asks each of 40 students how many books they bought last year.
Irina18 [472]

Answer/Step-by-step Explanation:

We are given the chart attached below showing no. of books bought by each of the 40 students.

=>Required:

a. % of students who bought 20 or more books (20-24 books)

b. Show that the estimated mean no. of books = 9.5 (i.e. we are to show/calculate the estimated mean for the data given which should be 9.5)

==>SOLUTION:

a. % of students who bought 20 - 24 books = no of students who bought 20-24 books ÷ total number of students multiplied by 100

From the chart, checking the column that represents 20-24, we have 2 students who bought 20 or more books.

Therefore, % of students who bought 20 or more books = \frac{2}{40}*100

= \frac{200}{40}

= 5%

b. To calculate the estimated mean no. of books bought, which should give us 9.5, we would use the formula μ = (∑mf)/N

Where μ = estimated mean

∑ = summation

m = class midpoint

f = frequency

N = population

Estimated mean can be calculated in 3 simple steps as follows:

=>STEP 1: Find mid-point of each class (i.e. m). Thus,

Class 0 - 4 = 2

Class 5 - 9 = 7

Class 10 - 14 = 12

Class 15 - 19 = 17

Class 20 - 24 = 22

STEP 2: Multiply each mid-point by its corresponding class frequency (i.e. mf). Thus,

For Class 0 - 4, we have (2)(11) = 22

For Class 5 - 9, we have (7)(8) = 56

For Class 10 - 14, we have (12)(13) = 156

For Class 15 - 19, we have (17)(6) = 102

For, Cass 20 - 24, we have (22)(2) = 44

STEP 3: Add each value we got from Step 2 and divide by 40 i.e. \frac{∑mf}{N}

Thus,

\frac{22 + 56 + 156 + 102 + 44}{40}

= \frac{380}{40}

= 9.5

Estimated mean (μ) = 9.5

8 0
2 years ago
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