The answer is C. transportation is a service.
I dont really know. you dont know how big the walls are and how far 1 gallon goes so figure how far 1 gallon goes and then divide it by the 1,162.5
We are asked to determine the present value of an annuity that is paid at the end of each period. Therefore, we need to use the formula for present value ordinary, which is:
![PV_{ord}=C(\frac{1-(1+i)^{-kn}}{\frac{i}{k}})](https://tex.z-dn.net/?f=PV_%7Bord%7D%3DC%28%5Cfrac%7B1-%281%2Bi%29%5E%7B-kn%7D%7D%7B%5Cfrac%7Bi%7D%7Bk%7D%7D%29)
Where:
![\begin{gathered} C=\text{ payments each period} \\ i=\text{ interest rate} \\ n=\text{ number of periods} \\ k=\text{ number of times the interest is compounded} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20C%3D%5Ctext%7B%20payments%20each%20period%7D%20%5C%5C%20i%3D%5Ctext%7B%20interest%20rate%7D%20%5C%5C%20n%3D%5Ctext%7B%20number%20of%20periods%7D%20%5C%5C%20k%3D%5Ctext%7B%20number%20of%20times%20the%20interest%20is%20compounded%7D%20%5Cend%7Bgathered%7D)
Since the interest is compounded semi-annually this means that it is compounded 2 times a year, therefore, k = 2. Now we need to convert the interest rate into decimal form. To do that we will divide the interest rate by 100:
![\frac{5.9}{100}=0.059](https://tex.z-dn.net/?f=%5Cfrac%7B5.9%7D%7B100%7D%3D0.059)
Now we substitute the values:
![PV_{ord}=4000(\frac{1-(1+0.059)^{-2(3)}}{\frac{0.059}{2}})](https://tex.z-dn.net/?f=PV_%7Bord%7D%3D4000%28%5Cfrac%7B1-%281%2B0.059%29%5E%7B-2%283%29%7D%7D%7B%5Cfrac%7B0.059%7D%7B2%7D%7D%29)
Now we solve the operations, we get:
![PV_{\text{ord}}=39462.50](https://tex.z-dn.net/?f=PV_%7B%5Ctext%7Bord%7D%7D%3D39462.50)
Therefore, the present value must be $39462.50
Answer:
B is the correct answer to your question
The turning point is (3,3). The x to make the absolute value negative would be 2. The ordered pair would then be (0,3)