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3 years ago

How does dry ice turn into carbon dioxide

Chemistry

2 answers:

abruzzese [7]3 years ago

6 0

<h2>PLEASE MARK BRAINLIEST! c:</h2>

Answer:

Dry ice doesn't melt and turn into a liquid at all, compared to ice-cubes that melt into a drink. In fact, dry ice doesn't melt. It sublimates. This means that it turns from a solid into a gas. So in this case, dry ice turns into carbon dioxide.

Dry-ice ---> Carbon dioxide

solid ---> gas

[Sublimation - the process in which a solid turns into a gas.]

I hope this helps!

Lady bird [3.3K]3 years ago

5 0

Answer:

Dry ice is carbon dioxide but frozen.

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4 years ago

A 155.0 g piece of copper at 128 oC is dropped into 250.0 g of water at 17.9 oC. (The specific heat of copper is 0.385 J/goC.) C

Mamont248 [21]

Answer:

$T_{eq}=23.85^oC$

Explanation:

Hello,

In this case, as the copper's heat loss is gained by the water, the following energetic relationship is:

$\Delta H_{Cu}=-\Delta H_{H_2O}$

Therefore the equilibrium temperature shows up as:

$m_{Cu}Cp_{Cu}(T_{Cu}-T{eq}) = m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})\\\\T_{eq}=\frac{m_{Cu}Cp_{Cu}T_{Cu}-m_{H_2O}Cp_{H_2O}T_{H_2O}}{m_{Cu}Cp_{Cu}-m_{H_2O}Cp_{H_2O}} \\$

Thus, by knowing that water's heat capacity is 4.18J/g°C, one obtains:

$T_{eq}=\frac{155.0g*0.385\frac{J}{g^oC}*128^oC+250.0g*4.18\frac{J}{g^oC}*17.9^oC}{155.0g*0.385\frac{J}{g^oC}+250.0g*4.18\frac{J}{g^oC}}=23.85^oC$

Best regards.

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3 years ago

Read 2 more answers