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GaryK [48]
3 years ago
10

1. Graph a wave with an

Chemistry
1 answer:
kiruha [24]3 years ago
5 0

Answer:

y = 5cos(\frac{2\pi }{6} x)

Explanation:

You can put that equation into a program like desmos on your browser and take a screenshot or use windows snippet tool.

Equation of a Wave: y = Acos(((2*pi)/B)x)

or

y = Acos(\frac{2\pi }{B} x)

A = Amplitude

B= Wavelength

You might be interested in
How many moles are in 45.8 g of calcium nitrate, Ca(NO3),?
Deffense [45]

Answer:

the number of moles is 0.279

Explanation:

The calculation of the number of moles of calcium nitrate, is given  below;

As We know that

Number of moles = mass of substance ÷ molecular weight

where

Mass of substance is 45.8g

And, the molecular weight is 164.088

so,

= 45.8 g ÷ 164.088

= 0.279moles

Thus , the number of moles is 0.279

We simply used the above formula so that the accurate value could arrive

4 0
3 years ago
Which of these takes place when a chemical change occurs?
zmey [24]

Answer:

In a chemical change, the atoms in the reactants rearrange themselves and bond together differently to form one or more new products with different characteristics than the reactants. When a new substance is formed, the change is called a chemical change.

Explanation:

7 0
3 years ago
Sublimation is snow or ice changing to a gas without melting. What must happen to the molecules for this to happen?
expeople1 [14]

Answer:Sublimation is the conversion between the solid and the gaseous phases of matter, with no intermediate liquid stage. For those of us interested in the water cycle, sublimation is most often used to describe the process of snow and ice changing into water vapor in the air without first melting into water.

Explanation:

6 0
2 years ago
Consider the compound hydroxyapatite, Ca10(PO4)6(OH)2. Name each ion present, give the charge of each ion and show that the form
emmainna [20.7K]
Ca₁₀(PO₄)₆(OH)₂  or  Ca(OH)₂·3Ca₃(PO₄)₂

PO₄³⁻   phosphate ion
OH⁻     oxyhydroxide ion
Ca²⁺     calcium ion

10*(+2)  +  6*(-3)  +  2*(-1) = 0
 10Ca²⁺      6PO₄³⁻      2OH⁻
7 0
2 years ago
Aqueous sulfuric acid will react with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . Suppose 6.9 g
satela [25.4K]

Answer:

5.6gNa_2SO_4

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

2NaOH(aq)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)

Therefore, since the masses of both of the reactants are given, one computes the available moles of sulfuric acid and those moles of it consumed by the sodium hydroxide as shown below:

n_{H_2SO_4}^{available}=6.9gH_2SO_4*\frac{1molH_2SO_4}{98gH_2SO_4}=0.0704molH_2SO_4\\n_{H_2SO_4}^{consumed\ by\ NaOH}=3.14gNaOH*\frac{1molNaOH}{40gNaOH}*\frac{1molH_2SO_4}{2molNaOH}=0.04molH_2SO_4

In such a way, since there is more available sulfuric acid than it that is consumed, the sodium hydroxide is the limiting reagent, consequently, the maximum mass of sodium sulfate turns out:

m_{Na_2SO_4}=0.04molH_2SO_4*\frac{1molNa_2SO_4}{1molH_2SO_4} *\frac{142.04gNa_2SO_4}{1molNa_2SO_4}=5.6gNa_2SO_4

Best regards.

5 0
3 years ago
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