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3 years ago

Hey pls show some working i need some serious help

Mathematics

1 answer:

Elden [556K]3 years ago

8 0

Answer:

$\frac{x^{12}y^{4}}{z^3}$

Step-by-step explanation:

Step 1: Multiply exponents

$\frac{y^{6/6}z^{-6/2}}{x^{-12}y^{-6/2}}$

Step 2: Simplify

$\frac{yz^{-3}}{x^{-12}y^{-3}}$

Step 3: Flip the negative exponents

$\frac{x^{12}y^{4}}{z^3}$

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Polygon ABCD is defined by the points A(-4,2) B(-2, 4), C(1, 3) & D(2,2). Match the coordinates of the points of the transfo

dalvyx [7]

Answer:

D'(-2, 2); C''(3, -1); A'''(4, -2); and B''(4, 2)

Step-by-step explanation:

See attachment for the figure.

For D', rotating the point (2, 2) 90° counterclockwise. This maps each point (x, y)→(-y, x); it takes (2, 2)→(-2, 2).

For C'', rotating the point (1, 3) 90° clockwise. This maps each point (x, y)→(y, -x); it takes (1, 3)→(3, -1).

For A''', rotating the point (-4, 2) 180° clockwise. This maps every point (x, y)→(-x, -y); it takes (-4, 2)→(4, -2).

For B'', rotating the point (-2, 4) 270° counterclockwise. This is the similar as rotating the point 90° clockwise. This maps every point (x, y)→(y, -x); it takes (-2, 4)→(4, 2).

8 0

3 years ago

In an August 2012 Gallup survey of 1,012 randomly selected U.S. adults (age 18 and over), 536 said that they were dissatisfied w

soldier1979 [14.2K]

Answer:

Yes, result is significant ; PVALUE < α

Step-by-step explanation:

Given :

x = 536

n = sample size = 1012

Phat = x / n = 536 / 1012 = 0.5296 = 0.53

H0 : P0 = 0.5

H1 : P0 > 0.5

Test statistic :

(Phat - P0) ÷ sqrt[(P0(1 - P0)) / n]

1-P0 = 1 - 0.5 = 0.5

(0.53 - 0.5) ÷ sqrt[(0.5*0.5)/1012]

0.03 ÷ 0.0157173

= 1.9087

Pvalue :

Using the Pvalue from test statistic :

Pvalue = 0.02815

To test if result is significant :

α = 0.05

0.02815 < 0.05

Pvalue < α ; Hence, result is significant at α=0.05; Hence, we reject H0.

3 0

3 years ago

Is 0.04 greater than 0.4

valentinak56 [21]

No
0.04 is actually smaller than 0.4 because the four is in the hundredths place which is smaller than the four in the tenths place of 0.4

7 0

3 years ago

Read 2 more answers

R^2+8r=-7 solve the equation with the quadratic formula showing work

Yuliya22 [10]

Answer:

Step-by-step explanation:

r²+8r=−7

Step 1: Subtract -7 from both sides.

r²+8r−(−7)=−7−(−7)

r²+8r+7=0

Step 2: Use quadratic formula with a=1, b=8, c=7.

r= $r=\frac{-b+or-\sqrt{-4ac} }{2a}$

$r=\frac{-8+or-\sqrt{(8})^2-4(1)(7) }{2(1)}$

7 0

3 years ago

Does anybody know how to do time with exponential decay

My name is Ann [436]

From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

$b_n=0.12\times b_{n-1}$

Why does this work? Initially, you start with 500 mL of air that you breathe in, so $b_1=500\text{ mL}$ . After the second breath, you have 12% of the original air left in your lungs, or $b_2=0.12\timesb_1=0.12\times500=60\text{ mL}$ . After the third breath, you have $b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}$ , and so on.

You can find the amount of original air left in your lungs after $n$ breaths by solving for $b_n$ explicitly. This isn't too hard:

$b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots$

and so on. The pattern is such that you arrive at

$b_n=0.12^{n-1}b_1$

and so the amount of air remaining after $50$ breaths is

$b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}$

which is a very small number close to zero.

5 0

3 years ago