Answer:
It’s B
Step-by-step explanation:
Answer: A. The number 23 is prime, but 36 is composite.
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Explanation:
Let's go through the possible answer choices
- A) This is true because 23 only has the factors 1 and 23. So that's why 23 is prime. We can say 36 is composite since 2 is a factor, ie 36 = 2*18.
- B) This is false because 33 is not prime. Note how 33 = 3*11, showing that 3 is a factor of 33.
- C) Similar to B, the statement "21 is prime" is false. Note how 21 = 3*7.
- D) Like the other false statements, 27 is not prime because 27 = 3*9.
Answer:
It will be the graph of two lines intersecting at two comma three with text on graph that reads One Solution 2, 3.
Step-by-step explanation:
The system of equations are
y - 2x = - 1 ............ (1) and
2y - x = 4 ........... (2)
Now, solving equations (1) and (2) we get,
2(2x - 1) - x = 4
{Substituting the value of y from equation (1) to equation (2)}
⇒ 4x - 2 - x = 4
⇒ 3x = 6
⇒ x = 2
Hence, from equation (1) we get,
y = 2x - 1 = 2(2) - 1 = 3
Therefore, the solution is (2,3).
So, it will be the graph of two lines intersecting at two comma three with text on the graph that reads One Solution 2, 3. (Answer)
Answer:
The equation of this line is y = 3x - 2
Step-by-step explanation:
In order to find this, start by finding two points on the line. We'll use (0,-2) and (1, 1). From there we start by finding the slope.
m(slope) = (y2 - y1)/(x2 - x1)
m = (1 - -2)/(1 - 0)
m = (1 + 2)/(1)
m = 3/1
m = 3
Now using that, we can plug it, along with a point into point-slope form to get the answer.
y - y1 = m(x - x1)
y - 1 = 3(x - 1)
y - 1 = 3x - 3
y = 3x - 2
Answer:
steps below
Step-by-step explanation:
f(x) = x⁷ – 6x⁶ + 8x⁵
f'(x) = 7x⁶ - 36x⁵ + 40x⁴
= x⁴ (7x² - 36x + 40) ... (1)
Critical point (x,y): x = 0 , x = (36 ± √(-36)²-4*7*40) / (2*7) = (18±2√11) / 7
x = 0 or x = 3.5 or x = 1.6
plug into (1): y = 0 , y = -394.3 , y = 10.1
extreme : <u>maximum (1.6 , 10.1)</u> <u>minimum (3.5 , -394.3)</u> ... turning points
x⁷ – 6x⁶ + 8x⁵ = x⁵ (x² - 6x + 8) = x⁵ (x-2) (x-4) =0
<u>real zeros: x = 0, x=2, x=4</u>
