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valentina_108 [34]
3 years ago
15

HOW DO YOU COUNT BY ONES FROM 368 TO 500 AND THEN CHANGE FOR A LARGER UNIT

Mathematics
1 answer:
tatyana61 [14]3 years ago
8 0
Use 2 ones to get to 370, use 3 tens to get to 400, use 1 hundred to get to 500. Hope this helped :)
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An elevator can hold a maximum of 1500 pounds. An average child weighs 75 pounds and the average adult weighs 150 pounds. The el
CaHeK987 [17]

<u>Let's take this problem step-by-step</u>:

<u>Let's first set up some variables</u>:

  • c: # of children
  • a: # of adults

<u>Let's examine the information given:</u>

  • Elevator can hold a maximum of 1500 pounds

          ⇒ average child is 75 pounds

          ⇒ average adult is 150 pounds

                 ⇒<em> therefore</em>: 75c + 150a\leq 1500

  • Elevator can fit no more than 14 people

          ⇒ <em>therefore</em>: c + a \leq 14

<u>Let's graph the equations</u>:

 75c+150a\leq 1500\\c+a\leq 14

    ⇒ look at the image attached

<u>The point at which the two graphs intersect:</u>

  ⇒ <em>is the solution that represents the amount of children and adults and </em>

<em>       their combine weight</em>

<em />

<u><em>With the horizontal axis being the # of children and vertical axis being the # of adults</em></u><em>:</em>

<em>  ⇒ the </em><em>solution is 8 children and 6 adults</em>

<em></em>

<u>Answer: 8 children and 6 adults</u>

<u></u>

Hope that helped!

<em />

               

7 0
1 year ago
Does anyone know this?
Bumek [7]

Answer:

B

Step-by-step explanation:

Initial mean = 156, Changed mean = 163.92

So, mean increases. Only condition that satisfies this is B.

7 0
3 years ago
Graph this piecewise function:
Pepsi [2]
Consider the function f(x<span>) = 2 x + 1. We recognize the equation y = 2 x + 1 as the Slope-Intercept form of the equation of a line with slope 2 and y-intercept (0,1). Think of a point moving on the </span>graph<span> of f. As the point moves toward the right it rises.
hope this helps

</span>
6 0
3 years ago
Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360
Natasha2012 [34]

\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]

\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

   \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]

5 0
3 years ago
Solve for b:<br><br> 6b+14 = -7-b
vladimir2022 [97]

Answer:

b = -3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

6b+14=−7−b

6b+14=−7+−b

6b+14=−b−7

Step 2: Add b to both sides.

6b+14+b=−b−7+b

7b+14=−7

Step 3: Subtract 14 from both sides.

7b+14−14=−7−14

7b=−21

Step 4: Divide both sides by 7.

\frac{7b}{7} = \frac{-21}{7}

b= -3

3 0
3 years ago
Read 2 more answers
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