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3 years ago

Several properties are used to evaluate this expression. Identify the property used in each step.

Mathematics

2 answers:

Lady bird [3.3K]3 years ago

5 0

Answer:

identify property

commutative property

associative property

Step-by-step explanation:

I took the assignment:)

Cat 101

2 years ago

Thank you!

Ghella [55]3 years ago

5 0

Answer:

the top one is identity of property. the middle one is indeed commutative property. the bottom one is associative property.

Step-by-step explanation:

I just took the assignment and got them right Good luck

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The probability that a person will have 0, 1, or 2 dental checkups per year is 0.3, 0.6, and 0.1, respectively. If seven people

Tom [10]

<h2>The required probability is 0.1224.</h2>

Step-by-step explanation:

Here, given:

The probability of having 0 dental checkup = 0.3

The probability of having 1 dental checkup = 0.6

The probability of having 2 dental checkup = 0.1

Number of people chosen at random = 7

So, the number of ways 2, 4 and 1 checkup are : $(\frac{7!}{2! \times 4! \times 1!} )$

Now, the combined probability that two will have no checkups, four will have one checkup, and one will have two checkups in the next year

= $(\frac{7!}{2! \times 4! \times 1!} ) \times (0.3)^2 \times (0.6)^4 \times (0.1)^1 = 0.1224$

Hence, the required probability is 0.1224.

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3 years ago

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3 years ago

How many numbers can be squared to get a value of 9?

Katena32 [7]

3 can be squared twice to get the value of 9. 3x3=9

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3 years ago

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chubhunter [2.5K]

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Step-by-step explanation:

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2 years ago

The length of a parasite in experiment A is 2.5 × 10–3 inch. The length of a parasite in experiment B is 1.25 × 10–4 inch. How m

torisob [31]

We have been given that :-

The length of a parasite in experiment A is $2.5 \times 10^{-3}$

The length of a parasite in experiment B is $1.25 \times 10^{-4}$

Let us write the the length of the parasite in experiment A in the exponent of -3.

$1.25 \times 10^{-4}= 0.125 \times 10^{-3}$

Clearly, the length of parasite in experiment A is greater than the length of parasite in experiment B.

The difference in the length is given by

$2.5 \times 10^{-3} -0.125 \times 10^{-4}$

$=2.375 \times 10^{-3}$

Therefore, the length of the parasite in experiment A is $=2.375 \times 10^{-3}$ inches greater than the length of the parasite in experiment B.

3 0

3 years ago

Read 2 more answers