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il63 [147K]
3 years ago
11

-8 -4 -2 -1 Pls help me

Mathematics
1 answer:
maksim [4K]3 years ago
8 0
I’m pretty sure it’s -9. check out quickmath.com that’ll help you !
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Ursula Vanov can invest $5,000 in a 1-year CD at 3% compounded monthly or a 1-year CD compounded daily. Determine the amount at
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Solving for the amount of maturity given that it is compounded monthly for 1 year with an interest of 3%, we have the formula and solution below:
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Step-by-step explanation:

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the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th
Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : \text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. 13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130      (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. 9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270      (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups =\dfrac{\text{Sum of combined students}}{\text{combined students}}

=\dfrac{400}{40}=10

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0
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