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AfilCa [17]
3 years ago
12

A: 1/2 inch B: 1 inch C: 2 inches D: 1/32 inch

Mathematics
1 answer:
mote1985 [20]3 years ago
4 0
The expression of the height is

a_n=8\cdot (\frac{1}{2})^{n-1}

the index "n" is the numbers of times that the ball is down, to n=1 the height is 8 inches, to n=2 the height is 4 inches.

An when n=5, the height is

a_5=8\cdot (\frac{1}{2})^{5-1}=8\cdot (\frac{1}{2})^4=\frac{1}{2} =0.5

the anwers is 0.5 inches
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100 POINTS AND BRAINLIEST ANSWER
polet [3.4K]

Answer:

Just took the test,  

1)d, 3

2)a, -13

3) c, y=-2x+6

4) c, f'(a)=8a+2

Step-by-step explanation:

For #3, graph f(x)=-x^2+5. Next graph y=-2x+6. You will see that the added equation touches at exactly the point (1,4). this make it the tangent line equation

5 0
3 years ago
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Find the substitution 2x+3y=-5 and y=-x+5
tatuchka [14]

Answer: x = 20, y = -15

Step-by-step explanation:

Since we already know that y=-x+5, we can just substitute in that value of y into the other equation:

2x+3y=-5\\2x+3(-x+5)=-5\\2x-3x+15=-5\\-x=-5-15\\-x=-20\\x=20

with the value of x, we can find the value of y:

y=-x+5=-20+5=-15

3 0
2 years ago
What is the sum of the measures of the interior angles of a 27-gon?
kvv77 [185]

Answer:

To figure out the total measure of the angles for a 27-gon, there is a formula.

n - 2 x 180*      (n is the number of sides, which would be 27)

27 - 2 = 25

25 x 180* = 4500*

The total measure of the angles of a 27-gon is: 4500*

Step-by-step explanation:

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7 0
3 years ago
Find the surface area of the surface given by the portion of the paraboloid z=3x2+3y2 that lies inside the cylinder x2+y2=4. (hi
natta225 [31]
Parameterize the part of the paraboloid within the cylinder - I'll call it S - by

\mathbf r(u,v)=\langle x(u,v),y(u,v),z(u,v)\rangle=\left\langle u\cos v,u\sin v,3u^2\right\rangle

with 0\le u\le2 and 0\le v\le2\pi. The region's area is given by the surface integral

\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=2}\int_{v=0}^{v=2\pi}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm du\,\mathrm dv
=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=2}u\sqrt{1+36u^2}\,\mathrm du\,\mathrm dv
=\displaystyle2\pi\int_{u=0}^{u=2}u\sqrt{1+36u^2}\,\mathrm du

Take w=1+36u^2 so that \mathrm dw=72u\,\mathrm du, and the integral becomes

=\displaystyle\frac{2\pi}{72}\int_{w=1}^{w=145}\sqrt w\,\mathrm dw
=\displaystyle\frac\pi{36}\frac23w^{3/2}\bigg|_{w=1}^{w=145}
=\dfrac\pi{54}(145^{3/2}-1)\approx101.522
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3 years ago
What is an equation for the following transformation of y=x: a vertical stretch by a factor of six.
BaLLatris [955]
Your answer is y=x-6
5 0
3 years ago
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