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7nadin3 [17]
4 years ago
12

A large bag of gumballs contains an equal amount of red, orange, yellow, blue, green, pink, purple, black, teal, and brown gumba

lls. Lane randomly selects 1 marble from the bag. Which of the following represents the probability of selecting an orange, green, teal, black, or purple gumball?
A. 0.6
B. 0.5
C. 0.7
D. 0.8
Mathematics
1 answer:
shtirl [24]4 years ago
3 0
B. 0.5 or 50%

The answer would be B because there are 10 possible colors of marbles and an equal amount of them in the bag, you want to know the probability of picking five of the ten possible colors which is 50% of the total marble colors.

Hope this helped! (Brainliest would be nice only if you think i deserve it)

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The following situation calls for a significance test. State the appropriate null hypothesis <img src="https://tex.z-dn.net/?f=H
harina [27]

Answer:

H_{0}: \sigma = 10\\

H_{a}: \sigma > 10\\        

Step-by-step explanation:

We are given the following in the question:

The organizers estimate that the variation in distance flown by the athletes will be σ = 10 meters.

This will be stated by the null hypothesis.

H_{0}: \sigma = 10\\

It was claimed that the organizers are underestimating the variation and the variation in distance is greater than 10.

This will be stated by the alternate hypothesis.

H_{a}: \sigma > 10\\

The parameter for the given hypothesis is standard deviation, \sigma.

3 0
3 years ago
Is (-1,2) a solution of y=-5x+7
Arlecino [84]

No, it is not. I will show you:

-1 = x  and 2 = y

2 = -5(-1) + 7

2 is not equal to 12. I hope this is right!

6 0
4 years ago
Read 2 more answers
Which expression calculates the speed in meters per second of an object that travels a distance of 40 m every 10 s?
RideAnS [48]
Speed = distance/time

So speed = 40/10

= 4m/s
3 0
4 years ago
Please help! I’ll mark brainliest
Usimov [2.4K]

Answer: 19 ≥ 3z + 1 ≥ - 5

8 0
3 years ago
12. A photocopier enlarges by a ratio of 7: 4. A picture
attashe74 [19]

Answer: 2 enlargments

Step-by-step explanation:

Use proportion for each enlargment you do

Side a=6cm                      Side b=4cm

6:4=x:7                             4:4=b1:7

7*6=4a1                             b1=28/4

a1=42/4                              b1=7 after first enlrge

a1=10.5 after first enlarge        7:4=b2:7

10.5:4=a2:7                         b2=49/4

a2=73.5/4                           xb2=12.5 after 2nd enlarge

a2=18.375  after 2nd enlarge                          

                                             12.5:4=b3:7

18,375:4=a3:7                       b3=21.875 cm after 3rd enlargement

a3=32.15after 3rd enlargement

Values after 3rd enlargement are higher than dimension given for picture wall

30 cm by 20 cm

8 0
3 years ago
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