The similarities between constructing a perpendicular line through a point on a line and constructing a perpendicular through a point off a line include:
- Both methods involve making a 90-degree angle between two lines.
- The methods determine a point equidistant from two equidistant points on the line.
<h3>What are perpendicular lines?</h3>
Perpendicular lines are defined as two lines that meet or intersect each other at right angles.
In this case, both methods involve making a 90-degree angle between two lines and the methods determine a point equidistant from two equidistant points on the line.
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Answer:
2,900
Step-by-step explanation:
So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
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Answer:
1568
Step-by-step explanation:
196/2=98
98*16=1586
Ryan can install 1568 square feet of flooring in 16 hours
Hope this helps!
Answer:
P(a junior or a senior)=1
Step-by-step explanation:
The formula of the probability is given by:
Where P(A) is the probability of occurring an event A, n(A) is the number of favorable outcomes and N is the total number of outcomes.
In this case, N is the total number of the students of statistics class.
N=18+10=28
The probability of the union of two mutually exclusive events is given by:
Therefore:
P(a junior or a senior) =P(a junior)+P(a senior)
Because a student is a junior or a senior, not both.
n(a junior)=18
n(a senior)=10
P(a junior)=18/28
P(a senior) = 10/28
P(a junior or a senior) = 18/28 + 10/28
Solving the sum of the fractions:
P(a junior or a senior) = 28/28 = 1
