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2 years ago

Find the equation of the line passing through the points (2, 4) and (3, 2). y = [? ]x + [ ]

Mathematics

1 answer:

PtichkaEL [24]2 years ago

7 0

Answer:

first find slope m

m=(4-2)/(2-3)

m= -2

so equation line is

y-y1=m(x-x1)

y-4=-2(x-2)

y-4=-2x+4

y=-2x+4+4

y=-2x+8

?=-2

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If r + 14 = -9, what justifies r = -23

kramer

Answer:

you subtract 14 from -9 and that justifies it

Step-by-step explanation:

Hope this helps

8 0

3 years ago

Read 2 more answers

4 points: A,B,C and D are marked in order on a line such that AB:AC = 3:5 and BD:CD= 7:2. If CD is 10cm long, find the length of

Jlenok [28]

ab:ac=3:5
bd:cd=7:2
if cd is 5 cm then cd=2:5 then ab=3:x

2:5=3:x
15=2x
x=15/2
x=7.5 cm
Happy studying! ^_^

4 0

3 years ago

What is the least common multiple of 15 and 6? Take notes and show your work.

Mariulka [41]

Hello!

The least common multiple is 3

Hope this helps!

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3 years ago

If the measure of one interior angle of a regular polygon is 144 degrees, find

Dmitrij [34]

There are 10 sides becuase the equation set up is $\frac{180(n-2)}{n}$ and equal it to 144.

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6 0

2 years ago

Find the equation of a circle with a center at (7,2) and a point on the circle at (2,5)?

monitta

Answer:

$(x-7)^2+(y-2)^2=34$

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h, k) is the center and r is the radius.

Since our center is at (7, 2), h = 7 and k = 2. Substitute:

$(x-7)^2+(y-2)^2=r^2$

Next, the since a point on the circle is (2, 5), y = 5 when x = 2. Substitute:

$(2-7)^2+(5-2)^2=r^2$

Solve for r:

$(-5)^2+(3)^2=r^2$

Simplify. Thus:

$25+9=r^2$

Finally, add:

$r^2=34$

We don't need to take the square root of both sides, as we will have the square it again anyways.

Therefore, our equation is:

$(x-7)^2+(y-2)^2=34$

4 0

2 years ago