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Serggg [28]
2 years ago
6

Find the equation of the line passing through the points (2, 4) and (3, 2). y = [? ]x + [ ]

Mathematics
1 answer:
PtichkaEL [24]2 years ago
7 0

Answer:

first find slope m

m=(4-2)/(2-3)

m= -2

so equation line is

y-y1=m(x-x1)

y-4=-2(x-2)

y-4=-2x+4

y=-2x+4+4

y=-2x+8

?=-2

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Which shows a correct order to solve this story problem?
Nesterboy [21]
Answer is C

3.2 oz + 4.7oz = 7.9 oz * 4 = 31.6oz total
6 0
3 years ago
If 1 factor of 3x3+7x2-7x-3 is (x+3) what are the other two factors
alexandr1967 [171]
<span>3x^3 + 7x^2 - 7x - 3</span>
= (x + 3)(x - 1)(3x + 1)

answer
other two factors (3x + 1) and (x - 1)
3 0
3 years ago
Complete the remainder of the table for the given function rule: y= x/4 + 7
babymother [125]

Let's replace x with -4 and simplify

y = (x/4) + 7

y = (-4/4) + 7

y = -1 + 7

y = 6

This means x = -4 and y = 6 pair up together.

So 6 goes in the box under the -4

----------------------------------------------------------

Repeat those steps for x = 0

y = (x/4) + 7

y = (0/4) + 7

y = 0 + 7

y = 7

So 7 goes in the box under the 0

----------------------------------------------------------

Let's repeat those steps for x = 4

y = (x/4) + 7

y = (4/4) + 7

y = 1 + 7

y = 8

So 8 goes in the box under the 4

----------------------------------------------------------

Lastly, for x = 8, we get

y = (x/4) + 7

y = (8/4) + 7

y = 2 + 7

y = 9

9 goes in the box under the 8

----------------------------------------------------------

The y outputs we got were: 6, 7, 8, 9

Notice how each time y increases by 1, x goes up by 4.

This means slope = rise/run = 1/4

We can think of x/4 as (1/4)x to help see that the slope is 1/4.

6 0
2 years ago
From a random sample of 41 teens, it is found that on average they spend 43.1 hours each week online with a population standard
Nadusha1986 [10]

Answer:

Step-by-step explanation:

We want to determine a 90% confidence interval for the mean amount of time that teens spend online each week.

Number of sample, n = 41

Mean, u = 43.1 hours

Standard deviation, s = 5.91 hours

For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean +/- z ×standard deviation/√n

It becomes

43.1 ± 1.645 × 5.91/√41

= 43.1 ± 1.645 × 0.923

= 43.1 ± 1.52

The lower end of the confidence interval is 43.1 - 1.52 =41.58

The upper end of the confidence interval is 43.1 + 1.52 =44.62

Therefore, with 90% confidence interval, the mean amount of time that teens spend online each week is between 41.58 and 44.62

8 0
3 years ago
George jogged a total distance of 9 and 1 over 2 miles during the months of October and November. If George only jogged 1 over 4
antiseptic1488 [7]

Hello,

Question:

George jogged a total distance of 9 and 1 over 2 miles during the months of October and November. If George only jogged 1 over 4 mile every day, which expression shows the number of days in which he went jogging?

We know:

He jogged 9 1/2 miles during October and November

1/4 mile every day

Answer:

9 and 1 over 2 divided by 1 over 4


6 0
3 years ago
Read 2 more answers
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