Question

SOMEONE HELP! (b+3)(c-4)

Answer 1

Answer

$bc - 4b + 3c - 12$

solution,

$(b + 3)(c - 4) \\ = b(c - 4) + 3(c - 4) \\ = bc - 4b + 3c - 12$

hope it helps..

Answer 2

Answer:

$bc - 4b + 3c - 12$ apply de disruptive property by multiplying each term of b+3 by each term of c -4