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bazaltina [42]
4 years ago
15

Need help!! Anyone ?

Mathematics
1 answer:
VMariaS [17]4 years ago
4 0
Me I need help plz help me
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Two arcades have different pricing structures. Arcade A costs $5 to enter and $0.60 per game. Arcade B costs $7 to enter and $0.
WARRIOR [948]

Answer:

10 games

Step-by-step explanation:

Let C be cost and x be number of games

Arcade A: C = 5 + 0.6x

Arcade B: C = 7 + 0.4x

for both arcades to be the same price, Both C's must be equal, hence we equate the right side of both equations:

5 + 0.6x = 7 + 0.4x   (subtract 5 fromboth sides)

0.6x = 7 + 0.4x - 5

0.6x = 2 + 0.4x  (subtract 0.4x from both sides)

0.6x - 0.4x = 2

0.2x = 2 (divide both sides by 0.2)

x = 2 / (0.2)

x = 10

7 0
3 years ago
Read 2 more answers
19 and use the bar thing to get answeer no links or i report
Agata [3.3K]
I think it’s C

Explanation: the blue yarn is 7 and the red yarn is 10 if you combine both as 7 + 10= 17
6 0
3 years ago
Determine whether the ordered pair is a solution of the linear equation. thanks in advance!!
Crank
YES IT IS!!

Work:

EQ: y= -x + 4
x= -6
y= 10

y= -x+4

1. 10= -(-6)+4
2. 10= +6+4
3. 10= 10
8 0
4 years ago
Escherichia coli cells are about 2.65 μm long and 0.480 μm in diameter. Calculate the volume of an E. coli cell, assuming the ce
zmey [24]

Answer:

4.7953 x 10⁻¹⁹ m³

Step-by-step explanation:

Length of the Escherichia coli cell (L) = 2.65 x 10⁻⁶ m

Diameter of the Escherichia coli  cell (D) = 0.480 x 10⁻⁶ m

The volume of cylinder in given by:

V= \frac{\pi D^2}{4}*L \\V= \frac{\pi (0.480*10^{-6})^2}{4}*2.65*10^{-6}\\V= 4.7953*10^{-19} m^3

The volume of an E. coli cell is 4.7953 x 10⁻¹⁹ m³.

6 0
4 years ago
35 POINTS. I need help! Please!
topjm [15]
There is no solution  for the first one

if you eliminate y   you get 2 equations
-13x - 13z = -25
-13x - 13x = -15    

- there is no solution to theses

a23  means the element in the second  row and the 3rd column

so its -5 
7 0
4 years ago
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