The width of the rectangle is twice the length of the rectangle
<h3>How to compare the dimensions of the rectangle?</h3>
The given parameters are:
Width = 4 cm
Length = 2 cm
Express 4 cm as 2 * 2 cm
Width = 2 * 2 cm
Substitute Length = 2 cm in Width = 2 * 2 cm
Width = 2 * Length
This means that the width of the rectangle is twice the length of the rectangle
Hence, the true statement is that the width of the rectangle is twice the length of the rectangle
Read more about rectangles at:
brainly.com/question/25292087
#SPJ1
Find the area of the rectangle. You can find the area of a rectangle with the following formula:

w = width, and l = length.
Plug in your width and length:

The area of the rectangle is 200 square centimeters.
The area of a square is also given by width * length. Multiply the sides together:

The area of a square is 4x^2.
Because you're cutting away the square from the rectangle, you will subtract the area of the square from the area of the rectangle. The following equation will be your answer:
The vertex is (8,7)
the minimum value is 7
the vertex form is y=(x-8)^2 +7
the minimum value of y=7
i hope this helps!
Answer:
4m-8
Step-by-step explanation: